Answer
397.2k+ views
Hint: Use the formula for centripetal force and force due to the magnetic field acting on a particle moving in a circular orbit. The force acting on the particle due to the magnetic field is equal to the centripetal force. From this relation, derive the equation for kinetic energy of the particle and solve it for kinetic energy of proton.
Formulae used:
The centripetal force \[{F_C}\] acting on an object in circular motion is
\[{F_C} = \dfrac{{m{v^2}}}{R}\] …… (1)
Here, \[m\] is the mass of the object, \[v\] is the velocity of the object and \[R\] is the radius of the circular path.
The magnetic force \[{F_B}\] acting on an particle is
\[{F_B} = qvB\] …… (2)
Here, \[q\] is charged on the particle, \[v\] is the velocity of the particle and \[B\] is the magnetic field.
The kinetic energy \[K\] of an object is
\[K = \dfrac{1}{2}m{v^2}\] …… (3)
Here, \[m\] is the mass of the object and \[v\] is the velocity of the object.
Complete step by step answer:
We have given that the kinetic energy of a deuteron is \[50\,{\text{keV}}\].
\[{K_d} = 50\,{\text{keV}}\]
The radius of the circular orbit in which the deuteron and proton are moving is \[0.5\,{\text{m}}\].
\[\Rightarrow R = 0.5\,{\text{m}}\]
Let \[{m_p}\] be the mass of the proton and \[{m_d}\] be the mass of the deuteron.Let us assume that the deuteron and proton are moving in the circular orbit with the same velocity.We are asked to determine the kinetic energy of the proton.For the deuteron moving in the circular orbit, the magnetic force \[{F_B}\] acting on it is equal to the centripetal force \[{F_C}\] acting on the deuteron.
\[{F_B} = {F_C}\]
Substitute for \[{F_B}\] and \[\dfrac{{{m_d}{v^2}}}{R}\] for \[{F_C}\] in the above equation.
\[q{v_d}B = \dfrac{{{m_d}{v^2}}}{R}\]
\[ \Rightarrow {m_d}{v^2} = qvBR\]
Therefore, according to equation (3), the kinetic energy \[{K_d}\] of deuteron is given by
\[ \Rightarrow {K_d} = \dfrac{1}{2}{m_d}{v^2} = \dfrac{{qvBR}}{2}\]
\[ \Rightarrow {K_d} = \dfrac{{qBR}}{{{m_d}v}}\] …… (4)
Similarly, the kinetic energy \[{K_p}\] of proton moving in the circular orbit is
\[ \Rightarrow {K_p} = \dfrac{1}{2}{m_p}{v^2} = \dfrac{{qvBR}}{2}\]
\[ \Rightarrow {K_p} = \dfrac{{qBR}}{{{m_p}v}}\] …… (5)
We know that the mass of the deuteron is twice the mass of the proton.
\[{m_d} = 2{m_p}\]
Let us divide equation (5) by equation (4).
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{\dfrac{{qBR}}{{{m_p}v}}}}{{\dfrac{{qBR}}{{{m_d}v}}}}\]
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{{m_d}}}{{{m_p}}}\]
Substitute \[2{m_p}\] for \[{m_d}\] in the above equation.
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{2{m_p}}}{{{m_p}}}\]
\[ \Rightarrow {K_p} = 2{K_d}\]
Substitute \[50\,{\text{keV}}\] for \[{K_d}\] in the above equation.
\[ \Rightarrow {K_p} = 2\left( {50\,{\text{keV}}} \right)\]
\[ \therefore {K_p} = 100\,{\text{keV}}\]
Therefore, the kinetic energy of a proton is \[100\,{\text{keV}}\].
Hence, the correct option is D.
Note:The students should keep in mind that while deriving the equation for kinetic energy of the proton and deuteron, the velocity of proton and deuteron should be considered the same as both the proton and deuteron are moving in the same circular orbit and same magnetic field B. If the velocities of proton and deuteron are taken different then we will not be able to reach to the answer.
Formulae used:
The centripetal force \[{F_C}\] acting on an object in circular motion is
\[{F_C} = \dfrac{{m{v^2}}}{R}\] …… (1)
Here, \[m\] is the mass of the object, \[v\] is the velocity of the object and \[R\] is the radius of the circular path.
The magnetic force \[{F_B}\] acting on an particle is
\[{F_B} = qvB\] …… (2)
Here, \[q\] is charged on the particle, \[v\] is the velocity of the particle and \[B\] is the magnetic field.
The kinetic energy \[K\] of an object is
\[K = \dfrac{1}{2}m{v^2}\] …… (3)
Here, \[m\] is the mass of the object and \[v\] is the velocity of the object.
Complete step by step answer:
We have given that the kinetic energy of a deuteron is \[50\,{\text{keV}}\].
\[{K_d} = 50\,{\text{keV}}\]
The radius of the circular orbit in which the deuteron and proton are moving is \[0.5\,{\text{m}}\].
\[\Rightarrow R = 0.5\,{\text{m}}\]
Let \[{m_p}\] be the mass of the proton and \[{m_d}\] be the mass of the deuteron.Let us assume that the deuteron and proton are moving in the circular orbit with the same velocity.We are asked to determine the kinetic energy of the proton.For the deuteron moving in the circular orbit, the magnetic force \[{F_B}\] acting on it is equal to the centripetal force \[{F_C}\] acting on the deuteron.
\[{F_B} = {F_C}\]
Substitute for \[{F_B}\] and \[\dfrac{{{m_d}{v^2}}}{R}\] for \[{F_C}\] in the above equation.
\[q{v_d}B = \dfrac{{{m_d}{v^2}}}{R}\]
\[ \Rightarrow {m_d}{v^2} = qvBR\]
Therefore, according to equation (3), the kinetic energy \[{K_d}\] of deuteron is given by
\[ \Rightarrow {K_d} = \dfrac{1}{2}{m_d}{v^2} = \dfrac{{qvBR}}{2}\]
\[ \Rightarrow {K_d} = \dfrac{{qBR}}{{{m_d}v}}\] …… (4)
Similarly, the kinetic energy \[{K_p}\] of proton moving in the circular orbit is
\[ \Rightarrow {K_p} = \dfrac{1}{2}{m_p}{v^2} = \dfrac{{qvBR}}{2}\]
\[ \Rightarrow {K_p} = \dfrac{{qBR}}{{{m_p}v}}\] …… (5)
We know that the mass of the deuteron is twice the mass of the proton.
\[{m_d} = 2{m_p}\]
Let us divide equation (5) by equation (4).
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{\dfrac{{qBR}}{{{m_p}v}}}}{{\dfrac{{qBR}}{{{m_d}v}}}}\]
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{{m_d}}}{{{m_p}}}\]
Substitute \[2{m_p}\] for \[{m_d}\] in the above equation.
\[ \Rightarrow \dfrac{{{K_p}}}{{{K_d}}} = \dfrac{{2{m_p}}}{{{m_p}}}\]
\[ \Rightarrow {K_p} = 2{K_d}\]
Substitute \[50\,{\text{keV}}\] for \[{K_d}\] in the above equation.
\[ \Rightarrow {K_p} = 2\left( {50\,{\text{keV}}} \right)\]
\[ \therefore {K_p} = 100\,{\text{keV}}\]
Therefore, the kinetic energy of a proton is \[100\,{\text{keV}}\].
Hence, the correct option is D.
Note:The students should keep in mind that while deriving the equation for kinetic energy of the proton and deuteron, the velocity of proton and deuteron should be considered the same as both the proton and deuteron are moving in the same circular orbit and same magnetic field B. If the velocities of proton and deuteron are taken different then we will not be able to reach to the answer.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)