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Hint- If a cube has an edge as $S$ then the lateral surface area of cube is given as $4{S^2}$ and the total surface area is given as $6{S^2}$ and if a cuboidal box has a length as $l$ , height as $h$ and width as $b$ then lateral surface area is given as $2h(l + b)$ and total surface area is given as $2(lb + bh + hl)$

Complete step-by-step answer:

Given that cube has each edge $S = 10{\text{ cm}}$

And cuboidal box has length $l = 12.5{\text{ cm}}$ ,width \[b = 10{\text{ }}{\text{cm}}\] , height $h = 8{\text{ cm}}$

Lateral surface area of cube $ = 4{S^2}$

By putting the value of $S$ , we get

Lateral surface area of cube

$

= 4 \times {10^2} \\

= 400{\text{ c}}{{\text{m}}^2} \\

$

Lateral surface area of cuboidal box $ = 2h(l + b)$

By putting the values of l, b, h, we get

Lateral surface area of cuboidal box

$

= 2 \times 8 \times (12.5 + 10) \\

= 360{\text{ c}}{{\text{m}}^2} \\

$

So, lateral surface area of cube is greater than cuboidal box

And the difference between their area is

$

= 400 - 360 \\

= 40{\text{ c}}{{\text{m}}^2} \\

$

Hence area difference is $ = 40{\text{ c}}{{\text{m}}^2}$

Total surface area of cube is given as $6{S^2}$

Putting the value of edge in above equation, we get

Total surface area of cube

$ = 6{S^2} \\

= 6 \times {10^2} \\

= 600{\text{ c}}{{\text{m}}^2} \\

$

Total surface area of cuboidal box is given as $2(lb + bh + hl)$

Putting the value of length $l = 12.5{\text{ cm}}$ ,width \[b = 10{\text{ }}{\text{cm}}\] , height $h = 8{\text{ cm}}$ above equation, we obtain

Total surface area of cuboidal box

$

= 2(lb + bh + hl) \\

= 2(12.5 \times 10 + 10 \times 8 + 12.5 \times 8) \\

= 2(125 + 80 + 100) \\

= 610{\text{ c}}{{\text{m}}^2} \\

$

Hence, the total surface area of cube is greater than the total surface area of cuboidal box

Therefore the area difference between them is $610 - 600 = 10{\text{ c}}{{\text{m}}^2}$

Note- These types of questions are based on formulas and to solve these types of questions you must remember the formulas. Try to remember the formulas with the help of diagrams and during solving the problem draw a rough diagram for your help. It helps in understanding the problem.

Complete step-by-step answer:

Given that cube has each edge $S = 10{\text{ cm}}$

And cuboidal box has length $l = 12.5{\text{ cm}}$ ,width \[b = 10{\text{ }}{\text{cm}}\] , height $h = 8{\text{ cm}}$

Lateral surface area of cube $ = 4{S^2}$

By putting the value of $S$ , we get

Lateral surface area of cube

$

= 4 \times {10^2} \\

= 400{\text{ c}}{{\text{m}}^2} \\

$

Lateral surface area of cuboidal box $ = 2h(l + b)$

By putting the values of l, b, h, we get

Lateral surface area of cuboidal box

$

= 2 \times 8 \times (12.5 + 10) \\

= 360{\text{ c}}{{\text{m}}^2} \\

$

So, lateral surface area of cube is greater than cuboidal box

And the difference between their area is

$

= 400 - 360 \\

= 40{\text{ c}}{{\text{m}}^2} \\

$

Hence area difference is $ = 40{\text{ c}}{{\text{m}}^2}$

Total surface area of cube is given as $6{S^2}$

Putting the value of edge in above equation, we get

Total surface area of cube

$ = 6{S^2} \\

= 6 \times {10^2} \\

= 600{\text{ c}}{{\text{m}}^2} \\

$

Total surface area of cuboidal box is given as $2(lb + bh + hl)$

Putting the value of length $l = 12.5{\text{ cm}}$ ,width \[b = 10{\text{ }}{\text{cm}}\] , height $h = 8{\text{ cm}}$ above equation, we obtain

Total surface area of cuboidal box

$

= 2(lb + bh + hl) \\

= 2(12.5 \times 10 + 10 \times 8 + 12.5 \times 8) \\

= 2(125 + 80 + 100) \\

= 610{\text{ c}}{{\text{m}}^2} \\

$

Hence, the total surface area of cube is greater than the total surface area of cuboidal box

Therefore the area difference between them is $610 - 600 = 10{\text{ c}}{{\text{m}}^2}$

Note- These types of questions are based on formulas and to solve these types of questions you must remember the formulas. Try to remember the formulas with the help of diagrams and during solving the problem draw a rough diagram for your help. It helps in understanding the problem.

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