Questions & Answers

Question

Answers

A. \[\dfrac{1}{4}\]

B. \[\dfrac{5}{9}\]

C. \[\dfrac{3}{4}\]

D. \[\dfrac{4}{9}\]

Answer
Verified

As we know that the number of boys in a class is 16.

And the number of girls in a class = 20.

So, the total number of students in this class will be = number of boys + number of girls = 16 + 20 = 36.

As we know from the concept of the probability that if there are n balls out of then x are of same type A then the probability of getting a ball of type A on random selection is equal to = \[\dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}\]. So, in this example favourable outcome will be ball of type A. So, probability = \[\dfrac{{{\text{Number of balls of type A}}}}{{{\text{Total number of balls}}}} = \dfrac{x}{n}\]

So, now let us come to the question. As we know that we have the probability of getting a girl on random selection. So, the favourable outcome must be a girl.

So, probability that the selected student is girl = \[\dfrac{{{\text{Number of girls}}}}{{{\text{Total number of students in class}}}} = \dfrac{{20}}{{36}} = \dfrac{5}{9}\]

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