A circular garden whose diameter is $28$m needs to be front, what would be the length of the facing wire required if a gardener makes a $3$ round of fence. Also, find the cost of the wire if it costs Rs. $30$meter.
Answer
562.8k+ views
Hint: Here first of all we will find the circumference of the circular garden and then will find the total length of the wire required for three rounds of fencing and accordingly by using the multiplication will find out the cost of the fencing wire for the circular garden in total.
Complete step-by-step answer:
Given that: Diameter $d = 28m$
Circumference of the circular garden can be given by –
$C = \pi d$
Place the known values in the above expression and also place $\pi = \dfrac{{22}}{7}$
$C = \dfrac{{22}}{7}(28)$
Common factors from the denominator and the numerator cancel each other out.
$C = 22(4)$
Simplify finding the product of the terms in the above expression –
$C = 88m$
Three rounds of fencing are to be done,
So total length of the wire required $ = 88 \times 3$
So total length of the wire required $ = 264$m
Now the cost of the wire is –
$1m = 30$Rs.
$\therefore 264m = ?$
Total cost of the wire $ = 264 \times 30$
Simplify finding the product of the terms –
Total cost of the wire $ = 7920$Rs.
Hence, the cost of fencing the circular garden three times will be Rs. $7920$
Note: The circumference of the circle is also known as the perimeter and it can also be calculated by using the formula $C = 2\pi r$ where r is the radius of the circle and it is half of the diameter. Read the word statements properly and find the cost of the wire.
Complete step-by-step answer:
Given that: Diameter $d = 28m$
Circumference of the circular garden can be given by –
$C = \pi d$
Place the known values in the above expression and also place $\pi = \dfrac{{22}}{7}$
$C = \dfrac{{22}}{7}(28)$
Common factors from the denominator and the numerator cancel each other out.
$C = 22(4)$
Simplify finding the product of the terms in the above expression –
$C = 88m$
Three rounds of fencing are to be done,
So total length of the wire required $ = 88 \times 3$
So total length of the wire required $ = 264$m
Now the cost of the wire is –
$1m = 30$Rs.
$\therefore 264m = ?$
Total cost of the wire $ = 264 \times 30$
Simplify finding the product of the terms –
Total cost of the wire $ = 7920$Rs.
Hence, the cost of fencing the circular garden three times will be Rs. $7920$
Note: The circumference of the circle is also known as the perimeter and it can also be calculated by using the formula $C = 2\pi r$ where r is the radius of the circle and it is half of the diameter. Read the word statements properly and find the cost of the wire.
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