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# A certain sample of cuprous sulphide is found to have composition $C{{u}_{1.8}}S$ because of incorporation of $C{{u}^{2+}}$ ions in the lattice. What is the mole percentage of the $C{{u}^{2+}}$ in total copper content in this crystal?A. $99.8%$B. $11.11%$C. $88.88%$D. None of these

Last updated date: 20th Jun 2024
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Hint: In this type of question, you need to find out the total loss in the given sample $C{{u}_{1.8}}S$ and then you can find out the mole percentage of the $C{{u}^{2+}}$ in total copper content in this crystal.

We know molecular formula of pure compound with $C{{u}^{+}}$ is $C{{u}_{2}}S$, but due to impurity of $C{{u}^{2+}}$ molecular formula becomes $C{{u}_{1.8}}S$.
We can write this as: $C{{u}_{2}}S\underset{\text{Impurity added}}{\longleftrightarrow}C{{u}_{1.8}}S$
From this we can find total loss copper i.e.,
$=\,Initial\,-\,Final$
$=2-1.8=0.2$
Therefore, percentage of $C{{u}^{2+}}$ in total copper content is given as
$=\,\dfrac{Initial\,-\,Final}{Final}\,\,\times 100$
Substituting the values in above formula we get,
$=\dfrac{0.2}{1.8}\times 100=11.11%$
Hence, mole percentage of $C{{u}^{2+}}$ in total copper content is $11.11%$

So, the correct answer is Option B.

In both $C{{u}_{2}}S$ and $C{{u}_{1.8}}S$, electrical neutrality is maintained. Atom is said to be electrically neutral when the overall charge of the atom is zero.
Copper sulphide is a chemical compound of copper and sulphur, it has the chemical formula $C{{u}_{2}}S$. It is basically found in nature as the mineral chalcocite.