# A card is drawn from a pack of $52$ cards at random. The probability of getting

Neither an ace nor a king card is:

${\text{A}}{\text{.}}$$\frac{2}{{13}}$

${\text{B}}{\text{.}}$$\frac{{11}}{{13}}$

${\text{C}}{\text{.}}$$\frac{4}{{13}}$

${\text{D}}{\text{.}}$ $\frac{8}{{13}}$

Answer

Verified

385.2k+ views

Hint: - Total number of ace cards in a pack of $52$ cards is $4$ and the total Number of king card is $4$. That means the number of required cards in pack is $44$.

We have to find a probability of getting neither an ace nor a king.

As we know:

A deck of cards contains $52$ cards. They are divided into four suits: Spades, diamonds, clubs and hearts each suit has $13$ cards: in which $1$ ace cards and three picture cards: jack, king and queen. In this question we neither need king nor is ace that means number of required cards $44$.

$p\left( A \right) = \frac{{N\left( E \right)}}{{N\left( S \right)}}$

This is the formula of finding the probability of any event $A$ where $N\left( E \right)$is the number of favorable outcomes and $N\left( S \right)$ is total outcomes or sample space.

Probability of getting neither an ace nor a king is=$\frac{{44}}{{52}} = \frac{{11}}{{13}}$

Option ${\text{B}}$ is correct.

Note:-You have to find total number of outcomes and total number of Favorable outcomes and just put in the formulae of finding the Probability. in this type of cards question you should have knowledge of cards distribution.

We have to find a probability of getting neither an ace nor a king.

As we know:

A deck of cards contains $52$ cards. They are divided into four suits: Spades, diamonds, clubs and hearts each suit has $13$ cards: in which $1$ ace cards and three picture cards: jack, king and queen. In this question we neither need king nor is ace that means number of required cards $44$.

$p\left( A \right) = \frac{{N\left( E \right)}}{{N\left( S \right)}}$

This is the formula of finding the probability of any event $A$ where $N\left( E \right)$is the number of favorable outcomes and $N\left( S \right)$ is total outcomes or sample space.

Probability of getting neither an ace nor a king is=$\frac{{44}}{{52}} = \frac{{11}}{{13}}$

Option ${\text{B}}$ is correct.

Note:-You have to find total number of outcomes and total number of Favorable outcomes and just put in the formulae of finding the Probability. in this type of cards question you should have knowledge of cards distribution.

Recently Updated Pages

Define absolute refractive index of a medium

Find out what do the algal bloom and redtides sign class 10 biology CBSE

Prove that the function fleft x right xn is continuous class 12 maths CBSE

Find the values of other five trigonometric functions class 10 maths CBSE

Find the values of other five trigonometric ratios class 10 maths CBSE

Find the values of other five trigonometric functions class 10 maths CBSE

Trending doubts

Which one of the following places is unlikely to be class 8 physics CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

What is 1 divided by 0 class 8 maths CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

What is pollution? How many types of pollution? Define it

Difference Between Plant Cell and Animal Cell

Find the HCF and LCM of 6 72 and 120 using the prime class 6 maths CBSE

Give 10 examples for herbs , shrubs , climbers , creepers