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Last updated date: 06th Dec 2023
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# A card is drawn from a pack of $52$ cards at random. The probability of getting Neither an ace nor a king card is:${\text{A}}{\text{.}}$$\frac{2}{{13}}$${\text{B}}{\text{.}}$$\frac{{11}}{{13}}$${\text{C}}{\text{.}}$$\frac{4}{{13}}$${\text{D}}{\text{.}}$ $\frac{8}{{13}}$

Hint: - Total number of ace cards in a pack of $52$ cards is $4$ and the total Number of king card is $4$. That means the number of required cards in pack is $44$.
A deck of cards contains $52$ cards. They are divided into four suits: Spades, diamonds, clubs and hearts each suit has $13$ cards: in which $1$ ace cards and three picture cards: jack, king and queen. In this question we neither need king nor is ace that means number of required cards $44$.
$p\left( A \right) = \frac{{N\left( E \right)}}{{N\left( S \right)}}$
This is the formula of finding the probability of any event $A$ where $N\left( E \right)$is the number of favorable outcomes and $N\left( S \right)$ is total outcomes or sample space.
Probability of getting neither an ace nor a king is=$\frac{{44}}{{52}} = \frac{{11}}{{13}}$
Option ${\text{B}}$ is correct.