Answer
425.4k+ views
Hint: We will use the law of conservation of momentum which is given as initial momentum of the system will be equal to final momentum of the system to determine the final velocity of the combined block. Then we will use the expression for kinetic energy to find the kinetic energy of the given system using the velocity we found. Kinetic energy is directly proportional to mass and square of the velocity of the body.
Formula used:
\[\begin{align}
& {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}} \\
& K.E=\dfrac{1}{2}m{{v}^{2}} \\
\end{align}\]
Complete step by step answer:
Firstly we will draw a diagram for understanding the situation better.
Here, the mass of the bullet is taken as \[m\].
Mass of the block is taken as \[M\].
Velocity of the bullet is taken as \[v\].
And velocity of the block is zero as it is initially at rest.
Now, we will use the law of conservation of momentum to find the velocity of the combined block whose mass will be \[M+m\]. That is,
\[mv+M\times 0=\left( m+M \right){{v}_{f}}\]
\[\begin{align}
& \Rightarrow mv=\left( m+M \right){{v}_{f}} \\
& \Rightarrow {{v}_{f}}=\dfrac{m}{\left( m+M \right)}v \\
\end{align}\]
So, the final velocity of the combined block is found to be, \[{{v}_{f}}=\dfrac{m}{\left( m+M \right)}v\].
Now, we will use this velocity to find the kinetic energy of the combined block. Kinetic energy is given as,
\[K.E=\dfrac{1}{2}m{{v}^{2}}\]
We have the mass of the combined block as \[M+m\].
\[\begin{align}
& \Rightarrow K.E=\dfrac{1}{2}\left( m+M \right){{\left( \dfrac{m}{\left( m+M \right)}v \right)}^{2}} \\
&\Rightarrow K.E=\dfrac{1}{2}\left( m+M \right)\times \dfrac{{{m}^{2}}}{{{\left( m+M \right)}^{2}}}{{v}^{2}} \\
& \Rightarrow K.E=\dfrac{1}{2}m{{v}^{2}}\times \dfrac{m}{\left( m+M \right)} \\
\end{align}\]
Hence, we have found the kinetic energy of composite block as\[\dfrac{1}{2}m{{v}^{2}}\times \dfrac{m}{\left( m+M \right)}\].
Hence, the correct answer is option A.
Note:
We must be very careful while doing problems like this. The sign of velocity has a major role in determining the momentum. In this case the velocity of all the objects and systems is in the same direction which we have taken as positive. But we must remember that we will need to use sign convention if any of the colliding particles or the composite system has a change in direction in velocity.
Formula used:
\[\begin{align}
& {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}} \\
& K.E=\dfrac{1}{2}m{{v}^{2}} \\
\end{align}\]
Complete step by step answer:
Firstly we will draw a diagram for understanding the situation better.
![seo images](https://www.vedantu.com/question-sets/ebe84690-cd6b-4aa8-9474-3bb6056ae5df1324923368693400407.png)
Here, the mass of the bullet is taken as \[m\].
Mass of the block is taken as \[M\].
Velocity of the bullet is taken as \[v\].
And velocity of the block is zero as it is initially at rest.
Now, we will use the law of conservation of momentum to find the velocity of the combined block whose mass will be \[M+m\]. That is,
\[mv+M\times 0=\left( m+M \right){{v}_{f}}\]
\[\begin{align}
& \Rightarrow mv=\left( m+M \right){{v}_{f}} \\
& \Rightarrow {{v}_{f}}=\dfrac{m}{\left( m+M \right)}v \\
\end{align}\]
So, the final velocity of the combined block is found to be, \[{{v}_{f}}=\dfrac{m}{\left( m+M \right)}v\].
Now, we will use this velocity to find the kinetic energy of the combined block. Kinetic energy is given as,
\[K.E=\dfrac{1}{2}m{{v}^{2}}\]
We have the mass of the combined block as \[M+m\].
\[\begin{align}
& \Rightarrow K.E=\dfrac{1}{2}\left( m+M \right){{\left( \dfrac{m}{\left( m+M \right)}v \right)}^{2}} \\
&\Rightarrow K.E=\dfrac{1}{2}\left( m+M \right)\times \dfrac{{{m}^{2}}}{{{\left( m+M \right)}^{2}}}{{v}^{2}} \\
& \Rightarrow K.E=\dfrac{1}{2}m{{v}^{2}}\times \dfrac{m}{\left( m+M \right)} \\
\end{align}\]
Hence, we have found the kinetic energy of composite block as\[\dfrac{1}{2}m{{v}^{2}}\times \dfrac{m}{\left( m+M \right)}\].
Hence, the correct answer is option A.
Note:
We must be very careful while doing problems like this. The sign of velocity has a major role in determining the momentum. In this case the velocity of all the objects and systems is in the same direction which we have taken as positive. But we must remember that we will need to use sign convention if any of the colliding particles or the composite system has a change in direction in velocity.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)