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# When 58 grams of water is heated from 275K to 365K, the waterA. Absorbs 21,820JB. Absorbs 377JC. Releases 5,220JD. Absorbs 242JE. Releases 90J

Last updated date: 20th Jun 2024
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Hint: Water has high heat capacity, i.e. it has a high ability to absorb heat to change its state. This phenomenon is due to the presence of hydrogen bonds and these bonds are cohesive and need more heat to break.

Complete step by step solution:
When water is heated then it absorbs and the energy absorbed by 58 g water on heating from 275 K to 365K is calculated by the given formula:

$q = ms\Delta T$.......... (1)

Where q is the amount of heat absorbed by water, m is the mass of water, s is the specific heat of water and $\Delta T$ is the temperature change.
Given that the mass of water is 50g.And we know the specific heat of water is 4.179 J/g℃ and the temperature change is calculated as:

$\Delta T = 365 - 275 = 90K$

Now put the value in equation (1), we get:

$q = 58 \times 4.179 \times 90 = 21820J$

So, the correct answer is Option A.