Answer
405.3k+ views
Hint: Empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. It does not provide any information about the arrangement or number of atoms. Also if we do the component analysis for any compound, we get the empirical formula.
Complete step by step answer:
As per the statement of the question, the empirical formula of the gas is given as $HF$. And by the definition of empirical formula, the empirical mass of $HF$ is equal to the sum of the mass of hydrogen ($H$) and mass of Fluorine ($F$). The mass of the hydrogen atom is known to be 1g and the mass of fluorine is given as 19g. The empirical mass of $HF$ is calculated as:
Empirical Mass = Mass of Hydrogen + Mass of Fluorine
$ \Rightarrow 1 + 19 = 20g$
At standard temperature and pressure, we know the volume of one mole of any gas 22.4 litres. Weight by mass ratio can be provided as:
$\dfrac{w}{M} = \dfrac{{5.6}}{{22.4}}$
$ \Rightarrow \dfrac{{10}}{M} = \dfrac{1}{4}$
$ \Rightarrow M = 40g$
As we know the empirical mass as 20g, The valency of the element ($n$)is calculated as:
$n = \dfrac{{Molecular{\text{ }}Mass}}{{Empirical{\text{ }}Mass}}$
$ \Rightarrow \dfrac{{40}}{{20}} = 2$
$\therefore $Molecular Formula = n $ \times $ Empirical Formula
\[ \Rightarrow 2 \times HF = {H_2}{F_2}\]
So, the correct answer is Option B.
Note: Empirical formula is the chemical formula that we obtain using composition analysis. The molecular formula of a compound represents the actual number of each element that occurs in the smallest existing unit. To determine the molecular formula of a compound, we need its composition and molecular weight of the compound. We can also use empirical formulas in the case where all data is not available.
Complete step by step answer:
As per the statement of the question, the empirical formula of the gas is given as $HF$. And by the definition of empirical formula, the empirical mass of $HF$ is equal to the sum of the mass of hydrogen ($H$) and mass of Fluorine ($F$). The mass of the hydrogen atom is known to be 1g and the mass of fluorine is given as 19g. The empirical mass of $HF$ is calculated as:
Empirical Mass = Mass of Hydrogen + Mass of Fluorine
$ \Rightarrow 1 + 19 = 20g$
At standard temperature and pressure, we know the volume of one mole of any gas 22.4 litres. Weight by mass ratio can be provided as:
$\dfrac{w}{M} = \dfrac{{5.6}}{{22.4}}$
$ \Rightarrow \dfrac{{10}}{M} = \dfrac{1}{4}$
$ \Rightarrow M = 40g$
As we know the empirical mass as 20g, The valency of the element ($n$)is calculated as:
$n = \dfrac{{Molecular{\text{ }}Mass}}{{Empirical{\text{ }}Mass}}$
$ \Rightarrow \dfrac{{40}}{{20}} = 2$
$\therefore $Molecular Formula = n $ \times $ Empirical Formula
\[ \Rightarrow 2 \times HF = {H_2}{F_2}\]
So, the correct answer is Option B.
Note: Empirical formula is the chemical formula that we obtain using composition analysis. The molecular formula of a compound represents the actual number of each element that occurs in the smallest existing unit. To determine the molecular formula of a compound, we need its composition and molecular weight of the compound. We can also use empirical formulas in the case where all data is not available.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)