
Write the order of magnitude of mass of an electron $9.1 \times {10^{ - 31}}kg$.
Answer
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Hint: an atom is made up of three constituent particles which are photons, electrons, and neutrons. An electron can be defined as the subatomic particle of an atom that carries a negative charge. The electrons are always bound to the nucleus which is also called a sub-shell.
Complete step by step answer:
As given in the question, the mass of an electron is $9.1 \times {10^{ - 31}}kg$ .
Here, we will change the mass of an electron from $kg$ to $g$ .
As we know, $1kg = 1000g$
Therefore, the mass of an electron becomes $9.1 \times {10^{ - 28}}g$ .
Now, electrons in one $kg$$ = \dfrac{{1000}}{{9.1 \times {{10}^{ - 28}}}}$
$ \Rightarrow \dfrac{{1000}}{{9.1}} \times {10^{28}}$
$ \Rightarrow 109.76 \times {10^{28}}$
$ \Rightarrow 1.0976 \times {10^{30}}$
$ \therefore {10^{30}}$
Hence, the magnitude of an object is ${10^{30}}$
Additional Information:
An electron was discovered by an English physicist J.J. Thomson in 1897 when he was investigating the cathode rays. Initially, he named the discovery of electrons as corpuscles. The discovery of electrons has played an important role in transforming the knowledge of atomic structure.
Electrons play an important role in various physical phenomena like electricity, magnetism, chemistry, and thermal conductivity and they are also involved in gravitational, electromagnetic, and weak interactions. The spin of an electron is $\dfrac{1}{2}$ and the charge on an electron is $1.6021 \times {10^{ - 19}}C$.
Note:
There are many applications of an electron, some of which are in electronics, welding, cathode ray tube, electron microscope, radiation therapy, lasers, gaseous ionization detectors, and particle accelerators. The antiparticle of an electron is known as the positron. When an electron and positron combine, they are annihilated to produce the gamma-ray photons.
Complete step by step answer:
As given in the question, the mass of an electron is $9.1 \times {10^{ - 31}}kg$ .
Here, we will change the mass of an electron from $kg$ to $g$ .
As we know, $1kg = 1000g$
Therefore, the mass of an electron becomes $9.1 \times {10^{ - 28}}g$ .
Now, electrons in one $kg$$ = \dfrac{{1000}}{{9.1 \times {{10}^{ - 28}}}}$
$ \Rightarrow \dfrac{{1000}}{{9.1}} \times {10^{28}}$
$ \Rightarrow 109.76 \times {10^{28}}$
$ \Rightarrow 1.0976 \times {10^{30}}$
$ \therefore {10^{30}}$
Hence, the magnitude of an object is ${10^{30}}$
Additional Information:
An electron was discovered by an English physicist J.J. Thomson in 1897 when he was investigating the cathode rays. Initially, he named the discovery of electrons as corpuscles. The discovery of electrons has played an important role in transforming the knowledge of atomic structure.
Electrons play an important role in various physical phenomena like electricity, magnetism, chemistry, and thermal conductivity and they are also involved in gravitational, electromagnetic, and weak interactions. The spin of an electron is $\dfrac{1}{2}$ and the charge on an electron is $1.6021 \times {10^{ - 19}}C$.
Note:
There are many applications of an electron, some of which are in electronics, welding, cathode ray tube, electron microscope, radiation therapy, lasers, gaseous ionization detectors, and particle accelerators. The antiparticle of an electron is known as the positron. When an electron and positron combine, they are annihilated to produce the gamma-ray photons.
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