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First we have to write Cube of natural numbers up to \[19\] is evaluated as follows:

The result of multiplying a natural number by itself triple times, this is known as cube of the natural number.

We get,

${1^3} = 1 \times 1 \times 1 = 1$

${2^3} = 2 \times 2 \times 2 = 8$

${3^3} = 3 \times 3 \times 3 = 27$

${4^3} = 4 \times 4 \times 4 = 64$

${5^3} = 5 \times 5 \times 5 = 125$

${6^3} = 6 \times 6 \times 6 = 216$

${7^3} = 7 \times 7 \times 7 = 343$

${8^3} = 8 \times 8 \times 8 = 512$

${9^3} = 9 \times 9 \times 9 = 729$

${10^3} = 10 \times 10 \times 10 = 1000$

${11^3} = 11 \times 11 \times 11 = 1331$

${12^3} = 12 \times 12 \times 12 = 1728$

${13^3} = 13 \times 13 \times 13 = 2197$

${14^3} = 14 \times 14 \times 14 = 2744$

${15^3} = 15 \times 15 \times 15 = 3375$

${16^3} = 16 \times 16 \times 16 = 4096$

${17^3} = 17 \times 17 \times 17 = 4913$

${18^3} = 18 \times 18 \times 18 = 5832$

${19^3} = 19 \times 19 \times 19 = 6859$

Also we can obtain cubes of odd numbers that are odd.

Then we write the odd numbers of the natural numbers.

They are any number that cannot be divisible by \[\;2\] and also the last digit ends with \[1,3,5,7,9\] are all odd numbers.

So, we can verify cubes of odd natural numbers are odd.

\[{1^3} = 1 \times 1 \times 1 = 1\]

${3^3} = 3 \times 3 \times 3 = 27$

${5^3} = 5 \times 5 \times 5 = 125$

${7^3} = 7 \times 7 \times 7 = 343$

${9^3} = 9 \times 9 \times 9 = 729$

${11^3} = 11 \times 11 \times 11 = 1331$

${13^3} = 13 \times 13 \times 13 = 2197$

${15^3} = 15 \times 15 \times 15 = 3375$

${17^3} = 17 \times 17 \times 17 = 4913$

${19^3} = 19 \times 19 \times 19 = 6859$

As it is very clear that the cube of odd natural numbers is odd.

Hence, we get the required answer and also verified.