Question

Which of the following particles will experience maximum magnetic force when projected with the same velocity perpendicular to a magnetic field?
A. Electron
B. Proton
C. \[{\text{H}}{{\text{e}}^{\text{ + }}}\]
D. \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\]

Answer 1

Hint: The magnetic force is induced by the motion of charges and is a product of the electromagnetic force, one of the four fundamental forces of nature. A magnetic attraction force exists between two objects containing charge moving in the same direction.

Complete step by step answer:
The magnetic force is induced by the motion of charges is,
\[{\text{F = qVB}}\]
Since the velocity and magnetic field are constant for all four choices, F is determined by the charge value. For proton, electron and \[{\text{H}}{{\text{e}}^{\text{ + }}}\], q\[ = 1\]
For \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\] q\[ = 2\]
So for \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\]maximum force is experienced.
Force on a moving charged particle,
F\[ = qVB\sin \theta \]
Here, $F$ is the energy that has been felt. The particle's charge is $q$. The charged particle's velocity is $V$.$B$ stands for magnetic field.

Force ($F$) is only dependent on charge $q$ since velocity $V$ and magnetic field $B$ are constant, and the angle between the magnetic field and charged particle is \[{90^0}\]. The charge on \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\] now exceeds that of an electron, proton, or\[{\text{H}}{{\text{e}}^{\text{ + }}}\]. As a result, \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\] has the greatest power. The force is proportional to the charge's magnitude $q$. So we can conclude that \[{\text{L}}{{\text{i}}^{{\text{ + + }}}}\] will experience maximum magnetic force when projected with the same velocity perpendicular to a magnetic field.

Note: The force acting on a charge moving in a magnetic field is often perpendicular to the velocity as well as the field. Any force acting perpendicular to the velocity has no effect on it (or the kinetic energy).