Question

Which of the following is divisible by 10?
A) 2011
B) 2014
C) 2015
D) 2120

Answer 1

Hint: Here, we are given 4 numbers and we need to find out which one of these 4 numbers is divisible by 10. A number is said to be divisible by a given number only if we divide them and get remainder 0. So, we will be checking all the 4 options and see which number when divided by 10 leaves remainder 0.

Complete step by step solution:
In this question, we are given 4 numbers and we are asked out of these 4 numbers which one is divisible by 10.
Now, a number is said to be divisible by some number, if we divide them and get remainder 0.
So, in this question, we need to find the number that when divided by 10 leaves remainder 0.
Let us check all the numbers and find out which one is divisible by 10.
Option A: 2011
When we divide 2011 by 10, we get
$ \Rightarrow 2011 = 10 \times 201 + 1$
Here, we can see that 2011 when divided by 10 leaves remainder 1.
Hence, 2011 is not divisible by 10.
Therefore, option A is incorrect.
Option B: 2014
When we divide 2014 with 10, we get
$ \Rightarrow 2014 = 2 \times 201 + 4$
Here, we can see that 2014 when divided by 10 leaves remainder 4.
Hence, 2014 is not divisible by 10.
Therefore, option B is incorrect.
Option C: 2015
When wee divide 2015 with 10, we get
$ \Rightarrow 2015 = 2 \times 201 + 5$
Here, we can see that 2015 when divided by 10 leaves remainder 5.
Hence, 2015 is not divisible by 10.
Therefore, option C is incorrect.
Option D: 2120
When we divide 2120 with 10, we get
$ \Rightarrow 2120 = 2 \times 212 + 0$
Here, we can see that 2120 when divided by 10 leaves remainder 0.
Hence, 2120 is divisible by 10. Therefore, option (D) is correct.

Note:
Note the following points while checking the divisibility of a number.
> Any number ending with an even number is always divisible by 2.
> Any number ending with 5 is always divisible by 5.
> Any number ending with 0 is always divisible by 2, 5 and 10.