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What is \[7\dfrac{1}{5}\]-\[6\dfrac{2}{5}\]?

Answer
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Hint: From the question given, we have been asked to find the solution to \[7\dfrac{1}{5}\]-\[6\dfrac{2}{5}\]. To solve this question, we have to know how to convert a mixed fraction into improper fraction and we have to know how to calculate improper fraction. So, first convert the mixed fractions to proper fractions, then make them like fractions such that their denominator is the same. Then, by subtracting the numerators, we can find the answer.

Complete step by step answer:
Let us define a mixed fraction, a whole number and a fraction combined into one mixed number. It is a combination of the whole number and a proper fraction. For example: \[2\dfrac{1}{3}\] here \[2\]is a whole number and \[\dfrac{1}{3}\] is a proper fraction.
Let us define an improper fraction, an improper fraction is a fraction in which the numerator is greater than or equal to the denominator. For example: \[\dfrac{5}{3}\].
To convert a mixed fraction into an improper fraction first we multiply the denominator of the proper fraction to the whole number attached with it and then we add the numerator.
By the definition of mixed fraction, we can convert the given mixed fraction into improper fraction as follows:
\[\Rightarrow \] \[7\dfrac{1}{5}\]=\[\dfrac{36}{5}\]
\[\Rightarrow \] \[6\dfrac{2}{5}\]=\[\dfrac{32}{5}\]
 \[\Rightarrow \] \[\dfrac{36}{5}-\dfrac{32}{5}\]
Since the denominators are same, we can subtract the numerators
As we discussed above, the denominators are same so by subtracting the numerators we get
\[\Rightarrow \] \[\dfrac{4}{5}\]

Hence the final solution to the given question is \[\dfrac{4}{5}\].

Note: Students should be well known about the concept of fractions and applications of fractions. Students should use easy methods to convert mixed fractions into improper fractions. The trick is to start by multiplying the whole number part of the mixed fraction by the denominator of the proper fraction part. Every mixed fraction is the sum of a whole number and a proper fraction.
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