We must know that the \[KMn{O_4}\] is a strong oxidizing agent that donates nascent oxygen to oxidize another substrate. Therefore, in the Alkaline medium \[KMn{O_4}\] will oxidize iodide to iodate by reducing itself.

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Hint: We must know that the \[KMn{O_4}\] is a strong oxidizing agent that donates nascent oxygen to oxidize another substrate. Therefore, in the Alkaline medium \[KMn{O_4}\] will oxidize iodide to iodate by reducing itself.

Complete step by step answer:
\[KMn{O_4}\] is a strong oxidizing agent only when it has an oxidation state with \[Mn\] is +7 states. \[KMn{O_4}\] will not act as an oxidizing agent in an acidic medium as there is a change of 5 electrons. So, in the alkaline medium only it will act as an oxidizing agent.
When alkaline \[KMn{O_4}\] is treated with\[KI\],\[\;{I^ - }\] is oxidized to $IO^3-$ by losing six electrons .or Iodide is oxidized to iodate ions.
Therefore, we can write the reaction as
\[
  2KMnO_4 + H_2O + KI \to 2Mn{O_2} + 2KOH + KIO_3 \\
  I + 6O{H^ - } \to IO{3^ - } + 3{H_2}O + 6e^- \\
 \]
\[KMn{O_4}\]​ acts as an oxidizing agent in this reaction, as in \[KMn{O_4}\],\[Mn\] is present in the highest oxidation state so it can readily donate 4 oxygen atoms to achieve its oxidation state +2.
So, the correct option is C

Note:
-Potassium Permanganate (\[KMn{O_4}\]) is an inorganic chemical compound. It is also known as Condy’s crystals or permanganate of potash
-We can use potassium permanganate in qualitative analysis to determine the permanganate value
-Also, we can use \[KMn{O_4}\] as a regeneration chemical in well water treatment for the removal of hydrogen sulfide and iron
-This compound is also used as a disinfectant to cure certain skin conditions like foot fungal infections, dermatitis
-Another important application of potassium permanganate is in the treatment of bacterial infections
\[KMn{O_4}\] is also known to be used in tanning leathers, printing fabrics
This compound can even be used as a bleaching agent, as a pesticide, and as an antiseptic