Question

There are $8$ isomers that have the chemical formula ${{C}_{5}}{{H}_{11}}Br$. How many of these are primary alkyl bromides?

Answer 1

Hint: Isomers are the species which have the same molecular formula but different structure. Consider the places where bromine can be displaced and different configuration of the main chain should be considered while answering the question.

Complete step by step solution:
Let’s start with discussing the isomer for better understanding of the question. Isomers are species which have the same molecular formula but different structure. Let’s take an example of butane and isobutene, both of these are having the same molecular formula that is ${{C}_{4}}{{H}_{10}}$ but when it comes to the structure, butane is a straight chain and isobutene is having a branch of $C{{H}_{3}}$ at $2nd$ carbon.

Coming back to our question we are given the molecular formula ${{C}_{5}}{{H}_{11}}Br$ and we have to find the total number of isomers. First we can place the Br in three different positions giving three different structures which are \[1-bromopentane,\text{ }2-\text{ }bromopentane,\text{ }3-bromopentane\] After this we can change the position of methyl groups and get five more structure which are \[1-bromo-2-methylbutane,\text{ }2-bromo-2-methylbutane,\text{ }2-bromo-3-methylbutane,\text{ }\]\[1-bromo-3-methylbutane,1-bromo-3-methylbutane,1-bromo\left[ 1 \right]2,2-dimethylpropane.\]These eight structures are possible
The haloalkanes can dissolve more in the organic solvent than in the water this is because the complex interaction between the haloalkanes and the creative molecules has the same potential as those broken by the unique and molecular haloalkanes.

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Note: We have to mind that Isomers are having similar molecular formulas and due to that they have weight, but isomers are having different molecular structure configuration and due to that they are having different physical properties but similar chemical properties.