Question

The value of $0.4125E05 \times 0.3781E01$ is?

Answer 1

Hint – In this particular type of question, E stands for exponential, so use the property that ($pEq = p \times {10^q}$), to simplify the given expression. Simply perform multiplication between the given two terms so use these concepts to reach the solution of the question.

Complete step by step solution:
Given equation is
$0.4125E05 \times 0.3781E01$
Now as we know in the above equation E stands for exponential (i.e. $9Ex = 9 \times {10^x}$ and $9E - x = 9 \times {10^{ - x}}$) so use this property in above equation we have,
$ \Rightarrow 0.4125E05 \times 0.3781E01 = \left( {0.4125 \times {{10}^5}} \right)\left( {0.3781 \times {{10}^1}} \right)$
Now simplify this equation we have,
$ \Rightarrow 0.4125E05 \times 0.3781E01 = \left( {0.4125} \right)\left( {0.3781} \right){10^{5 + 1}}$
$ \Rightarrow 0.4125E05 \times 0.3781E01 = \left( {0.4125} \right)\left( {0.3781} \right){10^6}$
$ \Rightarrow 0.4125E05 \times 0.3781E01 = \left( {.15596625} \right){10^6}$
So this is also written as according to above explanation
$ \Rightarrow 0.4125E05 \times 0.3781E01 = .15596625E06$
This is approximately equal to 0.1559662 E 06
So this is the required answer.
Hence option (C) is correct.

Note – The most common way to write the values in scientific notation is with the X 10 Exponent structure. We need not to get confused between Euler’s number (e) and this (E) as both are different. “Euler’s number” or “e” is the base of the natural logarithm, whose value is given as, e = 2.718 and E stands for the exponential term, so first simplify the given equation according to the above explained method then again simplify and write the simplified answer in exponent term as above, we will get the required answer.