The valency of nitrogen in nitrogen dioxide is:
A. 1
B. 2
C. 3
D. 4
Answer
553k+ views
Hint: Nitrogen dioxide is a gas with no net charge on the molecule. We know that valency of oxygen is 2. Write down the formula of nitrogen dioxide and calculate the valency of nitrogen to balance the valency over two atoms of oxygen in nitrogen dioxide.
Complete step by step solution:
Nitrogen dioxide is written as: \[N{O_2}\]. Oxygen has a valency of 2 and if we see on the periodic table, it is also electronegative out of the two. Valency of the element tells about the combining power of the element. Since the oxygen needs two more electrons to gain stability, its oxidation state will be -2. Since the net charge on the molecule is zero, we will assume the valency of nitrogen is $x$. Writing the balance equation to bring the net oxidation state of nitrogen dioxide as zero, we get,
$x + 2 \times ( - 2) = 0 \Rightarrow x = 4$. Thus the oxidation state of nitrogen is +4 and valency of nitrogen is 4. We can say that option D is correct.
Note: It is always the best way to first find the most electronegative of the elements comprising the compound and then equate the sum of the individual oxidation states to the net oxidation state of the molecule. This builds with practice but little memory in the beginning.
Complete step by step solution:
Nitrogen dioxide is written as: \[N{O_2}\]. Oxygen has a valency of 2 and if we see on the periodic table, it is also electronegative out of the two. Valency of the element tells about the combining power of the element. Since the oxygen needs two more electrons to gain stability, its oxidation state will be -2. Since the net charge on the molecule is zero, we will assume the valency of nitrogen is $x$. Writing the balance equation to bring the net oxidation state of nitrogen dioxide as zero, we get,
$x + 2 \times ( - 2) = 0 \Rightarrow x = 4$. Thus the oxidation state of nitrogen is +4 and valency of nitrogen is 4. We can say that option D is correct.
Note: It is always the best way to first find the most electronegative of the elements comprising the compound and then equate the sum of the individual oxidation states to the net oxidation state of the molecule. This builds with practice but little memory in the beginning.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

How many of the following diseases can be studied with class 11 biology CBSE

Which of the following enzymes is used for carboxylation class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

