
The thickness of $ 70 $ sheets is $ 128 $ mm. What is the thickness of each sheet in cm?
Answer
503.1k+ views
Hint: Here we will use the concepts of unitary method. Here we are given the cost of many quantities and we have to find the one quantity so we will use the division to get the required value for the thickness of one sheet. Then convert the unit of the resultant value in the form of cm.
Complete step-by-step answer:
The thickness of $ 70 $ sheets $ = 128 $ mm
The thickness of $ 1 $ sheet $ = ? $
Perform cross-multiplication, where the left side of one side is multiplied with the right side of the second equation.
$ = \dfrac{{128}}{{70}} $
Find the division of the above equation –
$ = 1.828571 $ mm
Now, to convert the mm to cm,
Use $ 1mm = 0.1cm $
$ \therefore 1.828571mm = 0.1 \times 1.828571 $ cm
Simplify the above expression –
$ \therefore 1.828571mm = 0.1828571cm $
This is the required solution.
Note: know the conversational relation between the different parameters like millimeters, meters and centimeters. Always read the given question and the required solution and its units. If the given is for one quantity and asked to find cost for many, that is one to many then use multiplication to get the required value.
Complete step-by-step answer:
The thickness of $ 70 $ sheets $ = 128 $ mm
The thickness of $ 1 $ sheet $ = ? $
Perform cross-multiplication, where the left side of one side is multiplied with the right side of the second equation.
$ = \dfrac{{128}}{{70}} $
Find the division of the above equation –
$ = 1.828571 $ mm
Now, to convert the mm to cm,
Use $ 1mm = 0.1cm $
$ \therefore 1.828571mm = 0.1 \times 1.828571 $ cm
Simplify the above expression –
$ \therefore 1.828571mm = 0.1828571cm $
This is the required solution.
Note: know the conversational relation between the different parameters like millimeters, meters and centimeters. Always read the given question and the required solution and its units. If the given is for one quantity and asked to find cost for many, that is one to many then use multiplication to get the required value.
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