Question

The rate law of a reaction between the substance A and B is given by the rate=$k{{[A]}^{n}}{{[B]}^{m}}$. On doubling the concentration of A and making the volume of B half the ratio of new rate to the earlier rate of reaction will be:

Answer 1

Hint:. The rate law could be a mathematical relationship obtained by comparing reaction rates with reactant concentrations. The reaction order is that the sum of the concentration term exponents during a rate law equation.

Complete step by step answer:
The Order of Reaction refers to the ability dependence of the speed on the concentration of every reactant. Thus, for a first-order reaction, the speed relies on the concentration of one species. The order of reaction is an experimentally determined parameter and might tackle a fractional value.
A reaction's rate law is also determined by the initial rates method. In order to work out a rate law we'd like to search out the values of the exponents n, m, and p, and also the value of the speed constant, k. If we are given the reaction orders for a reaction, we've the values of the coefficients we'd like to put in writing the speed law
The specific rate constant (k) is that the proportionality constant relating the speed of the reaction to the concentrations of reactants. the speed law and therefore the specific rate constant for any reaction must be determined experimentally. the worth of the speed constant is temperature dependent. Now let's come to the answer
Rate is given by,

$rate=k{{[A]}^{n}}{{[B]}^{m}}$

On Doubling the concentration of A and making Volume of B half, the new rate becomes
 $new\,rate=k{{[2A]}^{n}}{{[\dfrac{B}{2}]}^{m}}={{2}^{n-m}}k{{[A]}^{n}}{{[B]}^{m}}$
So, the ratio of the new rate to the old rate is ${{2}^{n-m}}$.

Note: The rate of a reaction is, perhaps, its most vital property because it dictates whether a reaction can occur during a lifetime. Knowing the speed law, an expression relating the speed to the concentrations of reactants, can help a chemist adjust the reaction conditions to urge a more suitable rate.