Question

- The moon is orbiting the Earth approximately once in $27$ days, what is the angle transversed by the Moon per day?

Answer 1

Hint: Given that the mean completes $1$ revolution around the earth in the total time of the $27$ days.
In one revolution around the earth, Angle formed will be ${360^0}$.

Complete step by step solution:
Given that moon completes $1$ revolution around the earth in the total time of $27$ days. In one revolution around the earth, the angle formed will be $360^\circ $. Since, the revolution is almost circular.
Hence, the angle transversed by the moon in $1$ day is $13.33$
$360^\circ $ is covered in $27$ days.
[Assuming moon’s orbit to be circular]
Angle traversed in one day is
$ = \dfrac{{360^\circ }}{{27}} = 13^\circ .33$
The moon orbits the earth once every $27.322$ days. It also takes approximately $27$ days for the moon to rotate once on its axis as a result, The moon does not seem to be spinning but appears to observers from earth to be keeping almost perfectly still scientists call this synchronous rotation.
The Side of the moon that perpetually faces earth is known as the null side. The opposite or back side is the bar side. Sometimes the bar side is called the dark side of the moon, but this is inaccurate when the moon is between the earth and the sun during the new moon phase, the back side of the moon is bathed in daylight.

Note:
The mean orbits earth in the prograde direction and complete one revolution relative to the star in about $27.32$ days (a sidereal month) and one revolution relative to the sun in about $24.53$ days (a synodic month) earth and the moon orbit about their barycenter( common center of mass) which lies about $4,600$km $(2400mi)$ from earth’s center (about $72\% $ of its radius) On arrange the distance to the moon is about $385000$ km from earth center, which corresponds to about to earth radii or $1.282$ light-seconds.