
Bond order of , , and is in order.
(A)
(B)
(C)
(D)
Answer
451.8k+ views
3 likes
Hint: First draw a molecular orbital diagram (MOT) where the atomic orbitals combine to form molecular orbitals. The total electrons associated with the molecules are filled in the MOT diagram.
To solve this question, we need to write the molecular orbital configuration. To find out the bond order from the molecular orbital configuration is:
Complete step by step answer:
Let’s first draw the MOT of the oxygen molecule. The oxygen molecule contains the 16 electrons. The MOT is as shown below:
First of all, we can write the molecular orbital configuration of the molecule. In a molecule, there are a total of 16 electrons. The molecular orbital configuration of the molecule is as follows:
There are 10 bonding and 6 nonbonding electrons in the orbitals according to the molecular orbital configuration.
Therefore,
=
Thus, the bond order is 2.
Similarly, in a molecule, there are 15 electrons. Therefore, the MOT diagram contains the 15 electrons. We will write down the MOT diagram for the orbital as the bonding between the and is the same as that of the . The MOT diagram is,
Therefore, the molecular orbital configuration of is as follows:
There are 10 bonding (including molecular orbitals formed by the orbitals) and 5 nonbonding electrons in the orbitals according to the molecular orbital configuration.
Therefore,
Therefore, the bond order of is .
In a molecule, there are 17 electrons. The MOT diagram holds a total of 17 electrons. The MOT diagram is as shown below,
So, the molecular orbital configuration is as follows:
There are 10 bonding electrons (including molecular orbitals formed by the orbitals.) and 7 nonbonding electrons.
Therefore,
Therefore, the bond order is .
In a molecule, there are 18 electrons. The MOT diagram is as shown below,
So, the molecular orbital configuration is as follows:
There are 10 bonding electrons and 8 nonbonding electrons.
Therefore,
Therefore, the bond order is 1.
So, the correct order of bond order is
So, the correct answer is “Option B”.
Note: You should notice that bond order is indirectly proportional to the length of the bond. The higher the bond order, the shorter and stronger will be the bond. The addition of each electron in the antibonding molecular orbital will decrease the bond order.
To solve this question, we need to write the molecular orbital configuration. To find out the bond order from the molecular orbital configuration is:
Complete step by step answer:
Let’s first draw the MOT of the oxygen molecule. The oxygen molecule

First of all, we can write the molecular orbital configuration of
There are 10 bonding and 6 nonbonding electrons in the orbitals according to the molecular orbital configuration.
Therefore,
=
Thus, the bond order
Similarly, in

Therefore, the molecular orbital configuration of
There are 10 bonding (including molecular orbitals formed by the
Therefore,
Therefore, the bond order of
In

So, the molecular orbital configuration is as follows:
There are 10 bonding electrons (including molecular orbitals formed by the
Therefore,
Therefore, the bond order
In

So, the molecular orbital configuration is as follows:
There are 10 bonding electrons and 8 nonbonding electrons.
Therefore,
Therefore, the bond order
So, the correct order of bond order is
So, the correct answer is “Option B”.
Note: You should notice that bond order is indirectly proportional to the length of the bond. The higher the bond order, the shorter and stronger will be the bond. The addition of each electron in the antibonding molecular orbital will decrease the bond order.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE

Give two reasons to justify a Water at room temperature class 11 chemistry CBSE
