
The hydrogen bonding is strongest in which one of the following sets?
A.) F-H--F
B.) O-H--S
C.) S-H--F
D.) F-H--O
Answer
594.6k+ views
Hint: To determine the strongest hydrogen bonding, we should be knowing the electronegativity of the element mentioned in the options. Knowing the position of the element in the periodic table, also gives an idea about the electronegativity.
Complete step-by-step answer:
The strength of the hydrogen bond depends upon the coulombic interaction between the electronegativity of the attached atom and hydrogen. Fluorine is the most electronegative element. So the F-H--F bond will be the strongest H bond.
So the correct option is Option A.
The high electronegativity of fluorine indicates that it has a high tendency to gain electrons from other elements with lower electronegativity.
Additional Information:
The electronegativity of oxygen is: 3.44
The electronegativity of fluorine is: 3.98
The electronegativity of sulphur is: 2.58
Fluorine is the most electronegative element because it has 5 electrons in its 2p orbital. The optimal electron configuration of the 2p orbital contains 6 electrons, so since fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
Note: We know that from top to bottom down the group electronegativity decreases. This is because the atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
Across a period the electronegativity increases as we move from left to right.
Complete step-by-step answer:
The strength of the hydrogen bond depends upon the coulombic interaction between the electronegativity of the attached atom and hydrogen. Fluorine is the most electronegative element. So the F-H--F bond will be the strongest H bond.
So the correct option is Option A.
The high electronegativity of fluorine indicates that it has a high tendency to gain electrons from other elements with lower electronegativity.
Additional Information:
The electronegativity of oxygen is: 3.44
The electronegativity of fluorine is: 3.98
The electronegativity of sulphur is: 2.58
Fluorine is the most electronegative element because it has 5 electrons in its 2p orbital. The optimal electron configuration of the 2p orbital contains 6 electrons, so since fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
Note: We know that from top to bottom down the group electronegativity decreases. This is because the atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
Across a period the electronegativity increases as we move from left to right.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

Name the metals and nonmetals in the first twenty class 11 chemistry CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

