
The hydrogen bonding is strongest in which one of the following sets?
A.) F-H--F
B.) O-H--S
C.) S-H--F
D.) F-H--O
Answer
592.5k+ views
Hint: To determine the strongest hydrogen bonding, we should be knowing the electronegativity of the element mentioned in the options. Knowing the position of the element in the periodic table, also gives an idea about the electronegativity.
Complete step-by-step answer:
The strength of the hydrogen bond depends upon the coulombic interaction between the electronegativity of the attached atom and hydrogen. Fluorine is the most electronegative element. So the F-H--F bond will be the strongest H bond.
So the correct option is Option A.
The high electronegativity of fluorine indicates that it has a high tendency to gain electrons from other elements with lower electronegativity.
Additional Information:
The electronegativity of oxygen is: 3.44
The electronegativity of fluorine is: 3.98
The electronegativity of sulphur is: 2.58
Fluorine is the most electronegative element because it has 5 electrons in its 2p orbital. The optimal electron configuration of the 2p orbital contains 6 electrons, so since fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
Note: We know that from top to bottom down the group electronegativity decreases. This is because the atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
Across a period the electronegativity increases as we move from left to right.
Complete step-by-step answer:
The strength of the hydrogen bond depends upon the coulombic interaction between the electronegativity of the attached atom and hydrogen. Fluorine is the most electronegative element. So the F-H--F bond will be the strongest H bond.
So the correct option is Option A.
The high electronegativity of fluorine indicates that it has a high tendency to gain electrons from other elements with lower electronegativity.
Additional Information:
The electronegativity of oxygen is: 3.44
The electronegativity of fluorine is: 3.98
The electronegativity of sulphur is: 2.58
Fluorine is the most electronegative element because it has 5 electrons in its 2p orbital. The optimal electron configuration of the 2p orbital contains 6 electrons, so since fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
Note: We know that from top to bottom down the group electronegativity decreases. This is because the atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
Across a period the electronegativity increases as we move from left to right.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

