The equation that represents Van’t Hoff general equation is.
A) $\pi = \dfrac{n}{V}RT$
B) $\pi = nRT$
C) $\pi = \dfrac{V}{n}RT$
D) $\pi = nVRT$
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Hint: We have to remember that the Van’t Hoff derives an equation based on the change in the equilibrium constant and change in temperature in a chemical reaction given the standard enthalpy change. With the help of Van’t Hoff equation, in the thermodynamic system we can explain the changes that occur in state function.
Complete step by step answer:
Think about a weakened arrangement of a volume V (in dm3) containing W grams of a substance having atomic weight M at an outright temperature T. At that point, centralization of the arrangement, \[C = n/V\] and No. of moles of the substance, \[n = W/M\].
By van't Haff: Boyle's law, at a consistent temperature, the osmotic weight of an answer is legitimately relative to its molar fixation or conversely corresponding to the volume of the arrangement. Subsequently,
\[\pi \propto C\] (When temperature is steady)
Van't Hoff Charle's law at the consistent focus the osmotic weight of a weaken arrangement is straightforwardly relative to the outright temperature (T) for example
\[\pi \propto T\]
\[\pi \propto CT\]
\[\pi = CRT\]
\[\pi = \dfrac{n}{V}RT\]
Where, $\pi $ is pressure, T is temperature, R is a gas constant, and n is the number of moles and V is volume.
The condition is called van't Hoff general arrangement condition.
R is steady of proportionality, likewise called general arrangement consistent or gas consistent.
Therefore, the option (A) is correct.
Note:
-We all know depression in melting point is directly associated with van't Hoff factor \[\left( i \right)\] consistent with which greater the worth of van't Hoff factor greater are going to be Depression in melting point.
-We can calculate the melting point depression using the formula,
\[\Delta Tf = i \times Kf \times molality\]
Where , the melting point depression is denoted as $\Delta Tf$ , \[Kf\] is that the melting point depression constant, and that \[i\] is that the van ‘t Hoff factor.
-The van't Hoff factor \[\left( i \right)\] is the total number of ions after dissociation or association or the total number of ions before dissociation or association.
Complete step by step answer:
Think about a weakened arrangement of a volume V (in dm3) containing W grams of a substance having atomic weight M at an outright temperature T. At that point, centralization of the arrangement, \[C = n/V\] and No. of moles of the substance, \[n = W/M\].
By van't Haff: Boyle's law, at a consistent temperature, the osmotic weight of an answer is legitimately relative to its molar fixation or conversely corresponding to the volume of the arrangement. Subsequently,
\[\pi \propto C\] (When temperature is steady)
Van't Hoff Charle's law at the consistent focus the osmotic weight of a weaken arrangement is straightforwardly relative to the outright temperature (T) for example
\[\pi \propto T\]
\[\pi \propto CT\]
\[\pi = CRT\]
\[\pi = \dfrac{n}{V}RT\]
Where, $\pi $ is pressure, T is temperature, R is a gas constant, and n is the number of moles and V is volume.
The condition is called van't Hoff general arrangement condition.
R is steady of proportionality, likewise called general arrangement consistent or gas consistent.
Therefore, the option (A) is correct.
Note:
-We all know depression in melting point is directly associated with van't Hoff factor \[\left( i \right)\] consistent with which greater the worth of van't Hoff factor greater are going to be Depression in melting point.
-We can calculate the melting point depression using the formula,
\[\Delta Tf = i \times Kf \times molality\]
Where , the melting point depression is denoted as $\Delta Tf$ , \[Kf\] is that the melting point depression constant, and that \[i\] is that the van ‘t Hoff factor.
-The van't Hoff factor \[\left( i \right)\] is the total number of ions after dissociation or association or the total number of ions before dissociation or association.