
The enthalpy of vaporization of water at \[{{100}^{\circ }}C\] is $40.63\,KJ\text{ }mo{{l}^{-1}}$ The value $\Delta U$ for this process:
(a)- $37.35\text{ }KJ\text{ }mo{{l}^{-1}}$
(b)- $39.08KJ\text{ }mo{{l}^{-1}}$
(c)- $42.19KJ\text{ }mo{{l}^{-1}}$
(d)- $43.73KJ\text{ }mo{{l}^{-1}}$
Answer
582.6k+ views
Hint: The internal energy of a system is calculated by the formula $\Delta H=\Delta U+\Delta {{n}_{g}}RT$ where $\Delta H$ is the change in enthalpy of the system, $\Delta U$ is the change in internal energy of the system, R is the gas constant, T is the temperature of the system, and $\Delta {{n}_{g}}$ is a difference of the number of moles of product and reactants.
Complete step by step answer:
Internal energy change is the heat absorbed or evolved at constant volume. It is denoted by $\Delta U$.
Enthalpy change of a system is equal to the heat absorbed or evolved by the system at constant pressure. It is denoted by $\Delta H$.
The internal energy change and change in enthalpy can be related as $\Delta H=\Delta U+\Delta {{n}_{g}}RT$
Where, $\Delta H$ is the change in enthalpy of the system and the question it is given $40.63\, KJ\text{ }mo{{l}^{-1}}$
R is the gas constant and its value is taken $8.314\text{ x 1}{{\text{0}}^{-3}}\text{ J}{{\text{K}}^{-1}}mo{{l}^{-1}}$
T is the temperature of the system.
It is always taken in Kelvin (K).
The temperature of the water is given \[{{100}^{\circ }}C\]. It has to be converted into Kelvin.
$T=100+273=373K$
The temperature is 373 K.
$\Delta {{n}_{g}}$ is the difference between the number of moles of products and reactants.
So, the reaction is:
${{H}_{2}}O(l)\to {{H}_{2}}O(g)$
$\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}$
So, the number of moles in the product is 1, and the number of moles in the reactant is 0 because the moles of liquid and solid are taken 0.
$\Delta {{n}_{g}}=1-0=1$
So, the internal energy change can be calculated.
$\Delta H=\Delta U+\Delta {{n}_{g}}RT$
$\Delta U=\Delta H-\Delta {{n}_{g}}RT$
$\Delta U=40.63-(1\ \text{x 8}\text{.314 x 1}{{\text{0}}^{-3}}\text{ x 373)}$
$\Delta U=37.53 KJ/mol$
So, the correct answer is “Option A”.
Note: The number of moles must be taken correctly. Only the moles of gaseous elements or compounds are taken for the calculation. The temperature must be converted to Kelvin if present in other forms.
Complete step by step answer:
Internal energy change is the heat absorbed or evolved at constant volume. It is denoted by $\Delta U$.
Enthalpy change of a system is equal to the heat absorbed or evolved by the system at constant pressure. It is denoted by $\Delta H$.
The internal energy change and change in enthalpy can be related as $\Delta H=\Delta U+\Delta {{n}_{g}}RT$
Where, $\Delta H$ is the change in enthalpy of the system and the question it is given $40.63\, KJ\text{ }mo{{l}^{-1}}$
R is the gas constant and its value is taken $8.314\text{ x 1}{{\text{0}}^{-3}}\text{ J}{{\text{K}}^{-1}}mo{{l}^{-1}}$
T is the temperature of the system.
It is always taken in Kelvin (K).
The temperature of the water is given \[{{100}^{\circ }}C\]. It has to be converted into Kelvin.
$T=100+273=373K$
The temperature is 373 K.
$\Delta {{n}_{g}}$ is the difference between the number of moles of products and reactants.
So, the reaction is:
${{H}_{2}}O(l)\to {{H}_{2}}O(g)$
$\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}$
So, the number of moles in the product is 1, and the number of moles in the reactant is 0 because the moles of liquid and solid are taken 0.
$\Delta {{n}_{g}}=1-0=1$
So, the internal energy change can be calculated.
$\Delta H=\Delta U+\Delta {{n}_{g}}RT$
$\Delta U=\Delta H-\Delta {{n}_{g}}RT$
$\Delta U=40.63-(1\ \text{x 8}\text{.314 x 1}{{\text{0}}^{-3}}\text{ x 373)}$
$\Delta U=37.53 KJ/mol$
So, the correct answer is “Option A”.
Note: The number of moles must be taken correctly. Only the moles of gaseous elements or compounds are taken for the calculation. The temperature must be converted to Kelvin if present in other forms.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

