The enthalpy of vaporization of water at \[{{100}^{\circ }}C\] is $40.63\,KJ\text{ }mo{{l}^{-1}}$ The value $\Delta U$ for this process:
(a)- $37.35\text{ }KJ\text{ }mo{{l}^{-1}}$
(b)- $39.08KJ\text{ }mo{{l}^{-1}}$
(c)- $42.19KJ\text{ }mo{{l}^{-1}}$
(d)- $43.73KJ\text{ }mo{{l}^{-1}}$
Answer
602.4k+ views
Hint: The internal energy of a system is calculated by the formula $\Delta H=\Delta U+\Delta {{n}_{g}}RT$ where $\Delta H$ is the change in enthalpy of the system, $\Delta U$ is the change in internal energy of the system, R is the gas constant, T is the temperature of the system, and $\Delta {{n}_{g}}$ is a difference of the number of moles of product and reactants.
Complete step by step answer:
Internal energy change is the heat absorbed or evolved at constant volume. It is denoted by $\Delta U$.
Enthalpy change of a system is equal to the heat absorbed or evolved by the system at constant pressure. It is denoted by $\Delta H$.
The internal energy change and change in enthalpy can be related as $\Delta H=\Delta U+\Delta {{n}_{g}}RT$
Where, $\Delta H$ is the change in enthalpy of the system and the question it is given $40.63\, KJ\text{ }mo{{l}^{-1}}$
R is the gas constant and its value is taken $8.314\text{ x 1}{{\text{0}}^{-3}}\text{ J}{{\text{K}}^{-1}}mo{{l}^{-1}}$
T is the temperature of the system.
It is always taken in Kelvin (K).
The temperature of the water is given \[{{100}^{\circ }}C\]. It has to be converted into Kelvin.
$T=100+273=373K$
The temperature is 373 K.
$\Delta {{n}_{g}}$ is the difference between the number of moles of products and reactants.
So, the reaction is:
${{H}_{2}}O(l)\to {{H}_{2}}O(g)$
$\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}$
So, the number of moles in the product is 1, and the number of moles in the reactant is 0 because the moles of liquid and solid are taken 0.
$\Delta {{n}_{g}}=1-0=1$
So, the internal energy change can be calculated.
$\Delta H=\Delta U+\Delta {{n}_{g}}RT$
$\Delta U=\Delta H-\Delta {{n}_{g}}RT$
$\Delta U=40.63-(1\ \text{x 8}\text{.314 x 1}{{\text{0}}^{-3}}\text{ x 373)}$
$\Delta U=37.53 KJ/mol$
So, the correct answer is “Option A”.
Note: The number of moles must be taken correctly. Only the moles of gaseous elements or compounds are taken for the calculation. The temperature must be converted to Kelvin if present in other forms.
Complete step by step answer:
Internal energy change is the heat absorbed or evolved at constant volume. It is denoted by $\Delta U$.
Enthalpy change of a system is equal to the heat absorbed or evolved by the system at constant pressure. It is denoted by $\Delta H$.
The internal energy change and change in enthalpy can be related as $\Delta H=\Delta U+\Delta {{n}_{g}}RT$
Where, $\Delta H$ is the change in enthalpy of the system and the question it is given $40.63\, KJ\text{ }mo{{l}^{-1}}$
R is the gas constant and its value is taken $8.314\text{ x 1}{{\text{0}}^{-3}}\text{ J}{{\text{K}}^{-1}}mo{{l}^{-1}}$
T is the temperature of the system.
It is always taken in Kelvin (K).
The temperature of the water is given \[{{100}^{\circ }}C\]. It has to be converted into Kelvin.
$T=100+273=373K$
The temperature is 373 K.
$\Delta {{n}_{g}}$ is the difference between the number of moles of products and reactants.
So, the reaction is:
${{H}_{2}}O(l)\to {{H}_{2}}O(g)$
$\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}$
So, the number of moles in the product is 1, and the number of moles in the reactant is 0 because the moles of liquid and solid are taken 0.
$\Delta {{n}_{g}}=1-0=1$
So, the internal energy change can be calculated.
$\Delta H=\Delta U+\Delta {{n}_{g}}RT$
$\Delta U=\Delta H-\Delta {{n}_{g}}RT$
$\Delta U=40.63-(1\ \text{x 8}\text{.314 x 1}{{\text{0}}^{-3}}\text{ x 373)}$
$\Delta U=37.53 KJ/mol$
So, the correct answer is “Option A”.
Note: The number of moles must be taken correctly. Only the moles of gaseous elements or compounds are taken for the calculation. The temperature must be converted to Kelvin if present in other forms.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What are the examples of C3 and C4 plants class 11 biology CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

10 examples of friction in our daily life

A body is said to be in dynamic equilibrium if A When class 11 physics CBSE

