
The earth’s magnetic field at some place on the magnetic equator of the earth is \[0.5 \times {10^{ - 4}}T\]. Consider the radius of the earth at the place as 6400 km. Then, the magnetic dipole moment of the earth is _____ $A{m^2}$.$\left( {{\mu _0} = 4\pi \times {{10}^{ - 7}}Tm{A^{ - 1}}} \right)$
A. $1.31 \times {10^{23}}$
B. $1.05 \times {10^{23}}$
C. $1.15 \times {10^{23}}$
D. $1.62 \times {10^{23}}$
Answer
574.8k+ views
Hint: In this question remember to use the concept of magnetic field also remember to use given values and substitute in the relation of magnetic field and magnetic dipole moment i.e. $B = \dfrac{{{\mu _0}M}}{{4\pi {{\left( {{R_e}} \right)}^3}}}$, using this information will help you to approach the solution of the question.
Complete answer:
According to the given information it is given that, magnetic field at some place on magnetic equator is given \[0.5 \times {10^{ - 4}}T\]where radius of earth is given as 6400 km
So, the given values are; $B = 0.5 \times {10^{ - 4}}T$, ${R_e}$= 6400 km or $6.4 \times {10^6}$m and ${\mu _0} = 4\pi \times {10^{ - 7}}Tm{A^{ - 1}}$
We know that by the relation of magnetic field and the magnetic dipole moment given as $B = \dfrac{{{\mu _0}M}}{{4\pi {{\left( {{R_e}} \right)}^3}}}$where M is the magnetic dipole moment of the body, ${R_e}$ is the radius of the earth, ${\mu _0}$represents absolute magnetic permeability of free space and B is the magnetic field by the body
Substituting the given values in the relation of magnetic field and magnetic dipole moment we get
$0.5 \times {10^{ - 4}} = \dfrac{{4\pi \times {{10}^{ - 7}}M}}{{4\pi \times {{\left( {6.4 \times {{10}^6}} \right)}^3}}}$
$ \Rightarrow $$M = \dfrac{{0.5 \times {{10}^{ - 4}} \times 262.14 \times {{10}^{18}}}}{{{{10}^{ - 7}}}}$
$ \Rightarrow $$M = \dfrac{{131.07 \times {{10}^{14}}}}{{{{10}^{ - 7}}}}$
$ \Rightarrow $$M = 131.07 \times {10^{21}}A{m^2}$
Or $M = 1.31 \times {10^{23}}A{m^2}$
Therefore, magnetic dipole moment at the equator of the earth will be equal to $1.31 \times {10^{23}}A{m^2}$
So, the correct answer is “Option A”.
Note:
In the above solution we used the term “magnetic field” which can be explained as the field under which the electric charge, electric current and magnetic objects experience the effect of magnetic force which acts perpendicular to the direction of velocity of charge, current or magnetic material the example of magnetic field is the magnetic force experienced by the magnetic materials on the earth where earth act as the source of magnetic field.
Complete answer:
According to the given information it is given that, magnetic field at some place on magnetic equator is given \[0.5 \times {10^{ - 4}}T\]where radius of earth is given as 6400 km
So, the given values are; $B = 0.5 \times {10^{ - 4}}T$, ${R_e}$= 6400 km or $6.4 \times {10^6}$m and ${\mu _0} = 4\pi \times {10^{ - 7}}Tm{A^{ - 1}}$
We know that by the relation of magnetic field and the magnetic dipole moment given as $B = \dfrac{{{\mu _0}M}}{{4\pi {{\left( {{R_e}} \right)}^3}}}$where M is the magnetic dipole moment of the body, ${R_e}$ is the radius of the earth, ${\mu _0}$represents absolute magnetic permeability of free space and B is the magnetic field by the body
Substituting the given values in the relation of magnetic field and magnetic dipole moment we get
$0.5 \times {10^{ - 4}} = \dfrac{{4\pi \times {{10}^{ - 7}}M}}{{4\pi \times {{\left( {6.4 \times {{10}^6}} \right)}^3}}}$
$ \Rightarrow $$M = \dfrac{{0.5 \times {{10}^{ - 4}} \times 262.14 \times {{10}^{18}}}}{{{{10}^{ - 7}}}}$
$ \Rightarrow $$M = \dfrac{{131.07 \times {{10}^{14}}}}{{{{10}^{ - 7}}}}$
$ \Rightarrow $$M = 131.07 \times {10^{21}}A{m^2}$
Or $M = 1.31 \times {10^{23}}A{m^2}$
Therefore, magnetic dipole moment at the equator of the earth will be equal to $1.31 \times {10^{23}}A{m^2}$
So, the correct answer is “Option A”.
Note:
In the above solution we used the term “magnetic field” which can be explained as the field under which the electric charge, electric current and magnetic objects experience the effect of magnetic force which acts perpendicular to the direction of velocity of charge, current or magnetic material the example of magnetic field is the magnetic force experienced by the magnetic materials on the earth where earth act as the source of magnetic field.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

