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The boiling point of ethanol is \[{78^0}C\] . What would it be in kelvin?

Answer
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Hint: Ethanol is a polar solvent with the molecular formula of \[{C_2}{H_5}OH\] . it belongs to an alcohol family due to the presence of \[ - OH\] group. Given that the boiling point of ethanol is \[{78^0}C\] to convert this temperature from Celsius to kelvin, we have to add the value of \[273\] to Celsius temperature.

Complete answer:
Temperature can be defined as the degree or intensity of heat contained in a body. It can be measured by a thermometer in different scales like Celsius, Fahrenheit and kelvin. The temperature from one scale to another scale can be converted.
Given that ethanol has a boiling point of \[{78^0}C\] . Ethanol is an alcohol with the molecular formula of \[{C_2}{H_5}OH\] . It belongs to the alcohol functional group. The presence of \[ - OH\] group in alcohols leads to the polarity of alcohols. The compounds containing the \[ - OH\] group are known as hydroxyl compounds.
The temperature in Celsius scale is given as \[{78^0}C\] , to convert the temperature in Celsius to kelvin scale the value of temperature in Celsius scale should add with a value of \[273\] , as one degree temperature in Celsius is equal to \[273\] degrees of kelvin.
\[{1^0}C = 273K\]
Thus, \[{78^0}C = 78 + 273 = 351K\]
The boiling point of ethanol is \[{78^0}C\] in kelvin scale it is equal to \[351K\]

Note:
The temperature on kelvin scale can be mostly used as the temperature in chemical reactions and various methods as it is the standard units. But the temperature will be given in Celsius scale only which can be converted into Celsius as the above conversion.