Answer
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Hint: We know that the molecular formula of bleaching powder is $Ca(OCl)Cl$. In the molecular structure of bleaching powder, $Ca$is the centred atom with $OCl$ and $Cl$ ions being branched to it.
Complete answer:
The structure of $C{{a}^{2+}}{{(OCl)}^{-}}C{{l}^{-}}$ is as follows:
We can see that calcium having a valency of +2, gains electrons from chlorine and oxygen. While oxygen having a valency of -2 shares an electron with the other chlorine. This proves that the chlorine atom attached directly to calcium has an oxidation state of -1. Calcium itself has an oxidation state of +2 which brings the following equation stating the oxidation state of $OCl$ to be -1. The sum of the oxidation states of all the atoms is 0 since the molecule is neutral.
$\begin{align}
& +2\ +\ (-1)\ +\ (-1)\ =\text{ }\ 0 \\
& Ca\text{ }Cl\text{ }OCl\text{ }Stability \\
\end{align}$
In the above equation, we see that stability is reached by the $Ca(OCl)Cl$ molecule when the oxidation state of $OCl$ is -1. We know that the oxidation state of oxygen is -2. Hence, to bring the oxidation state of $OCl$ as -1, the Chlorine atom attached to Oxygen must have an oxidation state of +1 as calculated from the following equation.
$(-2)\ +\ x=(-1)$
Where, x is the oxidation state of chlorine atom attached to oxygen.
From the above equation, we get the oxidation state of chlorine attached to oxygen to be +1.
Therefore, oxidation states of $Cl=+1,-1$
Hence, average oxidation state of$Cl=\text{ }\dfrac{(+1)+(-1)}{2}\text{ = }\dfrac{0}{2}\text{ = 0}$
The average oxidation state of $Cl$ atom in $Ca(OCl)Cl$ is zero.
Therefore, the correct answer is Option C.
Note: We should be knowing that bleaching powder is yellow in colour, having a strong smell of chlorine. It is soluble in water but aqueous solution is never found due to the presence of impurities. It loses chlorine by the action of carbon dioxide.
Although the usual oxidation state of chlorine is -1, since oxygen is more electronegative than chlorine, it adapts to the +1 oxidation state.
Complete answer:
The structure of $C{{a}^{2+}}{{(OCl)}^{-}}C{{l}^{-}}$ is as follows:
We can see that calcium having a valency of +2, gains electrons from chlorine and oxygen. While oxygen having a valency of -2 shares an electron with the other chlorine. This proves that the chlorine atom attached directly to calcium has an oxidation state of -1. Calcium itself has an oxidation state of +2 which brings the following equation stating the oxidation state of $OCl$ to be -1. The sum of the oxidation states of all the atoms is 0 since the molecule is neutral.
$\begin{align}
& +2\ +\ (-1)\ +\ (-1)\ =\text{ }\ 0 \\
& Ca\text{ }Cl\text{ }OCl\text{ }Stability \\
\end{align}$
In the above equation, we see that stability is reached by the $Ca(OCl)Cl$ molecule when the oxidation state of $OCl$ is -1. We know that the oxidation state of oxygen is -2. Hence, to bring the oxidation state of $OCl$ as -1, the Chlorine atom attached to Oxygen must have an oxidation state of +1 as calculated from the following equation.
$(-2)\ +\ x=(-1)$
Where, x is the oxidation state of chlorine atom attached to oxygen.
From the above equation, we get the oxidation state of chlorine attached to oxygen to be +1.
Therefore, oxidation states of $Cl=+1,-1$
Hence, average oxidation state of$Cl=\text{ }\dfrac{(+1)+(-1)}{2}\text{ = }\dfrac{0}{2}\text{ = 0}$
The average oxidation state of $Cl$ atom in $Ca(OCl)Cl$ is zero.
Therefore, the correct answer is Option C.
Note: We should be knowing that bleaching powder is yellow in colour, having a strong smell of chlorine. It is soluble in water but aqueous solution is never found due to the presence of impurities. It loses chlorine by the action of carbon dioxide.
Although the usual oxidation state of chlorine is -1, since oxygen is more electronegative than chlorine, it adapts to the +1 oxidation state.
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