
The antiderivative of every odd function is
A.An odd function
B.An even function
C.Neither even nor odd
D. Sometimes even, sometimes odd
Answer
590.1k+ views
Hint: We have to determine what is the antiderivative of every odd function. For finding whether the antiderivative of an odd function is odd or even, we will first let one function which is an odd function, and find the antiderivative of that odd function and see whether the obtained antiderivative is odd or even.
Complete step by step solution
The aim is to find whether the antiderivative of an odd function is odd or even.
We will first let function that is \[f\left( x \right) = x\] which represents the odd function as we know that the function is odd if and only if \[f\left( { - x} \right) = - f\left( x \right)\]
From this, we can verify that the function is an odd function,
\[
\Rightarrow f\left( { - 2} \right)\mathop = - f\left( 2 \right) \\
\Rightarrow - 2 = - 2 \\
\]
Next, we need to find the antiderivative of the above odd function that is the integral of the function \[f\left( x \right) = x\],
Thus, we get,
\[
\Rightarrow \int {f\left( x \right)dx = } \int {xdx} \\
\Rightarrow \int {f\left( x \right)dx = } \dfrac{{{x^2}}}{2} + c \\
\]
From this, we can let the antiderivative of the function \[f\left( x \right)\] as \[g\left( x \right)\].
Thus, we get,
\[ \Rightarrow g\left( x \right) = \dfrac{{{x^2}}}{2} + c\]
Here, the function \[g\left( x \right)\] is an even function as we know that the function is even if and only if \[g\left( { - x} \right) = g\left( x \right)\].
From this, we can verify that the function obtained is an even function.
Thus, we have,
\[
\Rightarrow g\left( { - 2} \right)\mathop = \left( 2 \right) \\
\Rightarrow \dfrac{{{{\left( { - 2} \right)}^2}}}{2}\mathop =\dfrac{{{{\left( 2 \right)}^2}}}{2} \\
\Rightarrow \dfrac{4}{2} = \dfrac{4}{2} \\
\]
Hence, we can conclude that the antiderivative of an odd function is an even function.
Thus, option B is correct.
Note: The antiderivative of a function is equal to the integration of that function. Odd and even functions are functions which satisfy particular symmetry relations with each other, with respect to taking additive inverses. After evaluating the antiderivative verify whether it is an odd function or even function.
Complete step by step solution
The aim is to find whether the antiderivative of an odd function is odd or even.
We will first let function that is \[f\left( x \right) = x\] which represents the odd function as we know that the function is odd if and only if \[f\left( { - x} \right) = - f\left( x \right)\]
From this, we can verify that the function is an odd function,
\[
\Rightarrow f\left( { - 2} \right)\mathop = - f\left( 2 \right) \\
\Rightarrow - 2 = - 2 \\
\]
Next, we need to find the antiderivative of the above odd function that is the integral of the function \[f\left( x \right) = x\],
Thus, we get,
\[
\Rightarrow \int {f\left( x \right)dx = } \int {xdx} \\
\Rightarrow \int {f\left( x \right)dx = } \dfrac{{{x^2}}}{2} + c \\
\]
From this, we can let the antiderivative of the function \[f\left( x \right)\] as \[g\left( x \right)\].
Thus, we get,
\[ \Rightarrow g\left( x \right) = \dfrac{{{x^2}}}{2} + c\]
Here, the function \[g\left( x \right)\] is an even function as we know that the function is even if and only if \[g\left( { - x} \right) = g\left( x \right)\].
From this, we can verify that the function obtained is an even function.
Thus, we have,
\[
\Rightarrow g\left( { - 2} \right)\mathop = \left( 2 \right) \\
\Rightarrow \dfrac{{{{\left( { - 2} \right)}^2}}}{2}\mathop =\dfrac{{{{\left( 2 \right)}^2}}}{2} \\
\Rightarrow \dfrac{4}{2} = \dfrac{4}{2} \\
\]
Hence, we can conclude that the antiderivative of an odd function is an even function.
Thus, option B is correct.
Note: The antiderivative of a function is equal to the integration of that function. Odd and even functions are functions which satisfy particular symmetry relations with each other, with respect to taking additive inverses. After evaluating the antiderivative verify whether it is an odd function or even function.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Which cell organelles are present in white blood C class 11 biology CBSE

What is the molecular geometry of BrF4 A square planar class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

Show that total energy of a freely falling body remains class 11 physics CBSE

