
The antiderivative of every odd function is
A.An odd function
B.An even function
C.Neither even nor odd
D. Sometimes even, sometimes odd
Answer
581.4k+ views
Hint: We have to determine what is the antiderivative of every odd function. For finding whether the antiderivative of an odd function is odd or even, we will first let one function which is an odd function, and find the antiderivative of that odd function and see whether the obtained antiderivative is odd or even.
Complete step by step solution
The aim is to find whether the antiderivative of an odd function is odd or even.
We will first let function that is \[f\left( x \right) = x\] which represents the odd function as we know that the function is odd if and only if \[f\left( { - x} \right) = - f\left( x \right)\]
From this, we can verify that the function is an odd function,
\[
\Rightarrow f\left( { - 2} \right)\mathop = - f\left( 2 \right) \\
\Rightarrow - 2 = - 2 \\
\]
Next, we need to find the antiderivative of the above odd function that is the integral of the function \[f\left( x \right) = x\],
Thus, we get,
\[
\Rightarrow \int {f\left( x \right)dx = } \int {xdx} \\
\Rightarrow \int {f\left( x \right)dx = } \dfrac{{{x^2}}}{2} + c \\
\]
From this, we can let the antiderivative of the function \[f\left( x \right)\] as \[g\left( x \right)\].
Thus, we get,
\[ \Rightarrow g\left( x \right) = \dfrac{{{x^2}}}{2} + c\]
Here, the function \[g\left( x \right)\] is an even function as we know that the function is even if and only if \[g\left( { - x} \right) = g\left( x \right)\].
From this, we can verify that the function obtained is an even function.
Thus, we have,
\[
\Rightarrow g\left( { - 2} \right)\mathop = \left( 2 \right) \\
\Rightarrow \dfrac{{{{\left( { - 2} \right)}^2}}}{2}\mathop =\dfrac{{{{\left( 2 \right)}^2}}}{2} \\
\Rightarrow \dfrac{4}{2} = \dfrac{4}{2} \\
\]
Hence, we can conclude that the antiderivative of an odd function is an even function.
Thus, option B is correct.
Note: The antiderivative of a function is equal to the integration of that function. Odd and even functions are functions which satisfy particular symmetry relations with each other, with respect to taking additive inverses. After evaluating the antiderivative verify whether it is an odd function or even function.
Complete step by step solution
The aim is to find whether the antiderivative of an odd function is odd or even.
We will first let function that is \[f\left( x \right) = x\] which represents the odd function as we know that the function is odd if and only if \[f\left( { - x} \right) = - f\left( x \right)\]
From this, we can verify that the function is an odd function,
\[
\Rightarrow f\left( { - 2} \right)\mathop = - f\left( 2 \right) \\
\Rightarrow - 2 = - 2 \\
\]
Next, we need to find the antiderivative of the above odd function that is the integral of the function \[f\left( x \right) = x\],
Thus, we get,
\[
\Rightarrow \int {f\left( x \right)dx = } \int {xdx} \\
\Rightarrow \int {f\left( x \right)dx = } \dfrac{{{x^2}}}{2} + c \\
\]
From this, we can let the antiderivative of the function \[f\left( x \right)\] as \[g\left( x \right)\].
Thus, we get,
\[ \Rightarrow g\left( x \right) = \dfrac{{{x^2}}}{2} + c\]
Here, the function \[g\left( x \right)\] is an even function as we know that the function is even if and only if \[g\left( { - x} \right) = g\left( x \right)\].
From this, we can verify that the function obtained is an even function.
Thus, we have,
\[
\Rightarrow g\left( { - 2} \right)\mathop = \left( 2 \right) \\
\Rightarrow \dfrac{{{{\left( { - 2} \right)}^2}}}{2}\mathop =\dfrac{{{{\left( 2 \right)}^2}}}{2} \\
\Rightarrow \dfrac{4}{2} = \dfrac{4}{2} \\
\]
Hence, we can conclude that the antiderivative of an odd function is an even function.
Thus, option B is correct.
Note: The antiderivative of a function is equal to the integration of that function. Odd and even functions are functions which satisfy particular symmetry relations with each other, with respect to taking additive inverses. After evaluating the antiderivative verify whether it is an odd function or even function.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

What is periodicity class 11 chemistry CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

Mention the basic forces in nature class 11 physics CBSE

