The ages of Hari and Harry are in the ratio 5: 7. Four years from now the ratio of their ages will be 3: 4. Find the sum of their present ages.
Answer
630k+ views
Hint: To find the sum, we write the present ages in terms of variable x. Then we write the ages after 4 years in terms of variable y. Then we write the relation between the present age and age after 4 years of Hari and Harry in equations of x and y and solve.
Complete step-by-step answer:
Given, the ratio of the present ages of Hari and Harry is 5:7.
Let the present age of Hari is 5x.
Let the present age of Harry is 7x.
Given, the ratio of the ages of Hari and Harry after 4 years is 3:4.
Let the present age of Hari is 3y.
Let the present age of Harry is 4y.
So according to the given, we have
5x + 4 = 3y - (1) and 7x + 4 = 4y - (2)
On solving the two equations we get x and y.
Multiply (1) by 4 and multiply (2) by 3, we get,
${\text{20x + 16 = 12y}}$ And ${\text{21x + 12 = 12y}}$ respectively.
Since the RHS of both the equation is same, we equate the two
⟹20x +16 = 21x +12
⟹x = 4
Now, the present ages of Hari and Harry are 5x and 7x, i.e.
The present age of Hari is 5x = 5 x 4 = 20 years
The present age of Harry is 7x = 7 x 4 = 28 years
Hence, the sum of their present ages = 20 + 28 = 48 years.
Note: In order to solve this type of problems the key is to write the given ratio in terms of unknown variables x and y. The main step is writing the relation between the present age and age after 4 years of Hari and Harry in equations. This becomes the clear case of a 2-equation 2-variables problem. Upon solving the two equations we get the values of the variables.
Complete step-by-step answer:
Given, the ratio of the present ages of Hari and Harry is 5:7.
Let the present age of Hari is 5x.
Let the present age of Harry is 7x.
Given, the ratio of the ages of Hari and Harry after 4 years is 3:4.
Let the present age of Hari is 3y.
Let the present age of Harry is 4y.
| Hari | Harry | |
| Present age | 5x | 7x |
| Age after 4 years | 3y | 4y |
So according to the given, we have
5x + 4 = 3y - (1) and 7x + 4 = 4y - (2)
On solving the two equations we get x and y.
Multiply (1) by 4 and multiply (2) by 3, we get,
${\text{20x + 16 = 12y}}$ And ${\text{21x + 12 = 12y}}$ respectively.
Since the RHS of both the equation is same, we equate the two
⟹20x +16 = 21x +12
⟹x = 4
Now, the present ages of Hari and Harry are 5x and 7x, i.e.
The present age of Hari is 5x = 5 x 4 = 20 years
The present age of Harry is 7x = 7 x 4 = 28 years
Hence, the sum of their present ages = 20 + 28 = 48 years.
Note: In order to solve this type of problems the key is to write the given ratio in terms of unknown variables x and y. The main step is writing the relation between the present age and age after 4 years of Hari and Harry in equations. This becomes the clear case of a 2-equation 2-variables problem. Upon solving the two equations we get the values of the variables.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

Difference between physical and chemical change class 11 chemistry CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

