Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Tendency to lose electrons shows the reducing property of the element. Which of the following orders are correct in terms of reducing property of the element?
This question has multiple correct options
(A) $ Na < K < Rb $
(B) $ Na > Mg > Al $
(C) $ {F^ - } < C{l^ - } < B{r^ - } < {I^ - } $
(D) $ Mg < Ca < Sr $

Answer
VerifiedVerified
416.4k+ views
Hint :The tendency of the element to lose electrons is known as its reducing property. As we move from the left to the right across the periodic table, the reducing character decreases. As we move from the top to the bottom in the periodic table, the reducing character increases.

Complete Step By Step Answer:
Reducing character is the ability of a substance to reduce other substances. The factors affecting the reducing property are ionization potential, atomic size, electro positivity or electronegativity, number of valence electrons, metallic and non-metallic character.
The elements sodium, potassium and rubidium belong to the same group. As we go down the group, the electropositive character increases and the reducing character increases. So, the given order of reducing property is correct.
The elements sodium, magnesium and aluminium belong to the same period. As we move across a period, the electropositive character decreases and the reducing character increases. So, the given order of reducing property is correct.
The elements fluorine, chlorine, bromine and iodine belong to the same group. As we go down the group, the electropositive character increases and the reducing character increases. So, the given order of reducing property is correct.
The elements magnesium, calcium and strontium belong to the same group. As we go down the group, the electropositive character increases and the reducing character increases. So, the given order of reducing property is correct.
Therefore, options A, B, C and D are correct.

Note :
As we go down the group in a periodic table, the size of the elements increases and the bond dissociation energy decreases. This facilitates the dissociation of hydrogen. So, reducing property increases down the group. As we move from left to right across a period, the effective nuclear charge acting on the outermost shell electrons increases and the electrons in the valence shell are held tightly. So, the tendency of atoms to lose electrons and the reducing power will decrease.