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Study the following chemical reactions.
$Fe + CuS{O_4} \to FeS{O_4} + Cu$
$2AgN{O_3} + Cu \to Cu{\left( {N{O_3}} \right)_2} + 2Ag$
The metals present in the reactions can be written in the increasing order of reactivity as:
A. $Fe,Cu,Ag$
B. $Cu,Fe,Ag$
C. $Ag,Fe,Cu$
D. $Ag,Cu,Fe$

Answer
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Hint: Reactivity is the relative ability of an atom, radical or molecule to undergo a chemical reaction with another atom, compound or molecule. Those compounds and elements which may ignite explosively or spontaneously show the high reactivity.

Complete step by step answer:
When iron reacts with cupric sulfate to form ferric sulfate and copper. It is a single displacement (substitution) reaction. The single displacement reaction is a chemical reaction in which one element is substituted by another in a compound and can be represented generically as $A + B - C \to A - C + B$ [A is more reactive than B]. It forms a stable and a new compound as products. According to the reactivity series, $Fe$ (iron) is more reactive element follows with copper $\left( {Cu} \right)$ then silver $\left( {Ag} \right)$ .The reactivity series includes the metal compounds in their order of reactivity. It is a chart listing metals in order of decreasing reactivity. A high reactive metal has more vigorously reacted with other substances and loses the electron easily to form positive ions (cations). According to the question, in the first reaction iron displaces the copper. So, iron is more reactive than copper. In the second reaction, copper substitutes the silver. It means copper is more reactive.
Hence, the increasing order is $Ag < Cu < Fe$.

So, the correct answer is Option D .

Note:
Caesium is the most reactive metal in the periodic table and reacts extremely violently and platinum is the least reactive metal. Francium is the most reactive metal even more than cesium but it is a laboratory-produced element in a minute quantity.