Question

Statement-I: Iodination of alkanes is carried out in the presence of iodic acid.
Statement-II: Iodic acid removes Iodine gas from the reaction mixture.
A.Statement 1 is true, Statement 2 is true; Statement 2 is the correct explanation of Statement 1
B.Statement 1 is true, Statement 2 is true; Statement 2 is not the correct explanation of Statement 1
C.Statement 1 is true, Statement 2 is false
D.Statement 1 is false, Statement 2 is true

Answer 1

Hint: To answer this question, you should recall the concept of halogenation of alkanes. Halogenation of an alkane produces a hydrocarbon derivative in which one or more halogen atoms have been substituted for hydrogen atoms.

Complete step by step answer:
-In halogenation of an alkane, the alkane is said to undergo fluorination, chlorination, bromination or iodination depending on the identity of the halogen reactant. Chlorination and bromination are the two usually used for halogenation reactions. Fluorination involves fluorine which results in explosive reactions due to high reactivity while iodination reactions go too slowly.
-The iodination reaction is reversible.
-\[HI\]is a strong reducing agent and it reduces alkyl iodide back to an alkane. The reaction can be represented as:
 \[R - H + {I_2} \rightleftharpoons R - I + HI\].
-To prevent this, some oxidizing agents such as mercuric oxide \[\left( {HgO} \right),\] iodic acid \[(HI{O_{3}})\]or dil. nitric acid \[(HN{O_{3}})\]is used which decompose \[HI\] acid. -The reaction can be represented as:
\[5R - H + 2{I_2} + HI{O_3} \to 5R - I + 3{H_{2}}O.\]
-As we can see, iodine is not evolved in this reaction, instead it is consumed.

Hence the correct answer to this question is option is C.

Note:
If electrophiles are added as a catalyst their role is to attach to the double bond and weaken it. Unlike alkene hydrogenation, catalysts do not allow the addition of molecular bromine or chlorine to generate nearby dichalcogenides. We have seen above that in the presence of ultraviolet light or a slight increase in temperature, the reaction of a halogen with alkane results in the formation of a haloalkane (alkyl halide). The phenomenon is explained by the reaction mechanism termed as the mechanism to halogenate. The carbon‐hydrogen bonds are low-polarity covalent bonds in the methane molecule. Alkanes are essential organic compounds and are unreactive. For the synthesis of further new compounds, they are subjected to different processes to make them reactive. The two reactions of further imports are combustion and halogenation.