
State any two reasons for necessity of modulation.
Answer
581.7k+ views
Hint: Modulation is a process by which low frequency audio signals can be transmitted to large distances by carrying it with high frequency carrier waves. So by modulation, some characteristics of high frequency carrier waves like frequency, amplitude or phase angle are varied according to instantaneous low frequency audio signal to transmit the audio signal to a large distance.
Formula used:
$\text{Wavelength=}\dfrac{\text{wave velocity}}{\text{frequency}}$
$\text{Power radiated}\ \propto {{\left( \dfrac{l}{\lambda } \right)}^{2}}$ $\lambda =\text{ wavelength, }l=\text{length of antenna}$
Complete step-by-step answer:
Need of modulation: Message signal also called baseband signal refers to the band of frequency of original signal produced at source. Audio signals have bandwidth of \[20KHz\]. So the low frequency signal wave cannot be transferred directly to long distance because of ;
1. Antenna length: To transmit a signal properly the height of the antenna should be comparable to the wavelength of the signal which is to be transferred (at least one-fourth in length). So the antenna can properly sense the time variation of the signal. Wavelength of signal is
$\text{Wavelength=}\dfrac{\text{wave velocity}}{\text{frequency}}$
As signals travels with speed of light$\left( 3\times {{10}^{8}} \right)$ also the frequency of audio signal is \[20KHz\]
So the wavelength of the signal is \[=\dfrac{3\times {{10}^{8}}\dfrac{m}{s}}{20KHz}=\dfrac{3\times {{10}^{8}}\dfrac{m}{s}}{20\times {{10}^{3}}Hz}=15000m=15km\]
So in order to transmit the audio signal the antenna length should be at least $5km$. But antennas of such height cannot be constructed or operated. If the carrier wave of frequency $1MHz$$\left( 1MHz={{10}^{6}}Hz \right)$ is used the antenna height is reduced to $200m-300m$
2. Power radiated by antenna: For an antenna of length $l$ it is seen that
$\text{Power radiated}\ \propto {{\left( \dfrac{l}{\lambda } \right)}^{2}}$
For the same antenna length the power radiated by short wavelength or high frequency signals will be large. If the audio signals with longer wavelength are transmitted to space they will die out after covering some distance due to low power radiated by antenna. So to transmit to a larger distance they are superimposed with high frequency carrier waves.
Note: To transmit low frequency audio signal to a very large distance it is superimposed with high frequency carrier wave. The carrier wave should have at-least twice the highest component of the audio signal. So the high frequency signal is the signal which is actually transmitted and carries the information signal or audio signal so it is called a carrier wave.
Formula used:
$\text{Wavelength=}\dfrac{\text{wave velocity}}{\text{frequency}}$
$\text{Power radiated}\ \propto {{\left( \dfrac{l}{\lambda } \right)}^{2}}$ $\lambda =\text{ wavelength, }l=\text{length of antenna}$
Complete step-by-step answer:
Need of modulation: Message signal also called baseband signal refers to the band of frequency of original signal produced at source. Audio signals have bandwidth of \[20KHz\]. So the low frequency signal wave cannot be transferred directly to long distance because of ;
1. Antenna length: To transmit a signal properly the height of the antenna should be comparable to the wavelength of the signal which is to be transferred (at least one-fourth in length). So the antenna can properly sense the time variation of the signal. Wavelength of signal is
$\text{Wavelength=}\dfrac{\text{wave velocity}}{\text{frequency}}$
As signals travels with speed of light$\left( 3\times {{10}^{8}} \right)$ also the frequency of audio signal is \[20KHz\]
So the wavelength of the signal is \[=\dfrac{3\times {{10}^{8}}\dfrac{m}{s}}{20KHz}=\dfrac{3\times {{10}^{8}}\dfrac{m}{s}}{20\times {{10}^{3}}Hz}=15000m=15km\]
So in order to transmit the audio signal the antenna length should be at least $5km$. But antennas of such height cannot be constructed or operated. If the carrier wave of frequency $1MHz$$\left( 1MHz={{10}^{6}}Hz \right)$ is used the antenna height is reduced to $200m-300m$
2. Power radiated by antenna: For an antenna of length $l$ it is seen that
$\text{Power radiated}\ \propto {{\left( \dfrac{l}{\lambda } \right)}^{2}}$
For the same antenna length the power radiated by short wavelength or high frequency signals will be large. If the audio signals with longer wavelength are transmitted to space they will die out after covering some distance due to low power radiated by antenna. So to transmit to a larger distance they are superimposed with high frequency carrier waves.
Note: To transmit low frequency audio signal to a very large distance it is superimposed with high frequency carrier wave. The carrier wave should have at-least twice the highest component of the audio signal. So the high frequency signal is the signal which is actually transmitted and carries the information signal or audio signal so it is called a carrier wave.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

