
State and explain coulomb’s inverse square law.
Answer
552.3k+ views
Hint: The fundamental unit of electric charge is called coulomb. Coulomb’s law gives the force between two charges separated by a distance. It is found that the electric charge of any system is always an integer multiple of the least amount of charge $e$, where $e$ is the charge of the proton or electron.
Complete step by step answer:
Coulomb’s law states that the force of attraction or repulsion between two point charges is proportional to the product of charges and inversely proportional to the square of the distance between them.
If ${q_1}$ and ${q_2}$ are the two-point charges separated by a distance $r$, then by Coulomb’s law
$F \propto \dfrac{{{q_1}{q_2}}}{{{r^2}}}$ or
$F = \dfrac{{k{q_1}{q_2}}}{{{r^2}}}$,
where $k$ is the constant of proportionality given by $k = \dfrac{1}{{4\pi \varepsilon }}$.
Here $\varepsilon $ is the permittivity of the medium. If the charges are kept in free space (air or vacuum), $k = \dfrac{1}{{4\pi {\varepsilon _0}}}$, where ${\varepsilon _0}$ is the permittivity of free space.
${\varepsilon _0} = 8.854 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}$
$\therefore \dfrac{1}{{4\pi {\varepsilon _0}}} = \dfrac{1}{{4 \times 3.14 \times 8.854 \times {{10}^{ - 12}}}} = 9 \times {10^9}N{m^2}{C^{ - 2}}$
$\therefore $ In air or vacuum, the force between two charges can be written as,
$F = \dfrac{1}{{4\pi {\varepsilon _0}}}\dfrac{{{q_1}{q_2}}}{{{r^2}}} = 9 \times {10^9}\dfrac{{{q_1}{q_2}}}{{{r^2}}}$
Additional Information:
One coulomb is defined as the quantity of charge which when placed at a distance of $1m$ in air or vacuum from an equal and similar charge experiences a repulsive force of $9 \times {10^9}N$. If charges are similar, Coulomb force $F$ is positive and it is repulsive in nature. If one charge is positive and the other is negative, Coulomb force $F$ is negative, and it is attractive in nature.
Note: The relative permittivity or (dielectric constant) ${\varepsilon _r}$ of a medium is defined as the ratio of the permittivity of the medium to the permittivity of free space. The magnitude of Coulomb force depends on the number of charges, the distance between the charges, and the nature of the media.
Complete step by step answer:
Coulomb’s law states that the force of attraction or repulsion between two point charges is proportional to the product of charges and inversely proportional to the square of the distance between them.
If ${q_1}$ and ${q_2}$ are the two-point charges separated by a distance $r$, then by Coulomb’s law
$F \propto \dfrac{{{q_1}{q_2}}}{{{r^2}}}$ or
$F = \dfrac{{k{q_1}{q_2}}}{{{r^2}}}$,
where $k$ is the constant of proportionality given by $k = \dfrac{1}{{4\pi \varepsilon }}$.
Here $\varepsilon $ is the permittivity of the medium. If the charges are kept in free space (air or vacuum), $k = \dfrac{1}{{4\pi {\varepsilon _0}}}$, where ${\varepsilon _0}$ is the permittivity of free space.
${\varepsilon _0} = 8.854 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}$
$\therefore \dfrac{1}{{4\pi {\varepsilon _0}}} = \dfrac{1}{{4 \times 3.14 \times 8.854 \times {{10}^{ - 12}}}} = 9 \times {10^9}N{m^2}{C^{ - 2}}$
$\therefore $ In air or vacuum, the force between two charges can be written as,
$F = \dfrac{1}{{4\pi {\varepsilon _0}}}\dfrac{{{q_1}{q_2}}}{{{r^2}}} = 9 \times {10^9}\dfrac{{{q_1}{q_2}}}{{{r^2}}}$
Additional Information:
One coulomb is defined as the quantity of charge which when placed at a distance of $1m$ in air or vacuum from an equal and similar charge experiences a repulsive force of $9 \times {10^9}N$. If charges are similar, Coulomb force $F$ is positive and it is repulsive in nature. If one charge is positive and the other is negative, Coulomb force $F$ is negative, and it is attractive in nature.
Note: The relative permittivity or (dielectric constant) ${\varepsilon _r}$ of a medium is defined as the ratio of the permittivity of the medium to the permittivity of free space. The magnitude of Coulomb force depends on the number of charges, the distance between the charges, and the nature of the media.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

