Question

What is the specific heat of ice at 0${}^\circ C$?

Answer 1

Hint: To solve this question we first need to know what specific heat is. The specific heat capacity of a substance is obtained when we divide the heat capacity of the substance by its mass. Its SI unit is joules per kelvin and kilogram or J/kg.K.

Complete answer:
The thermal capacity or the heat capacity of a substance is equal to the amount of heat that is required by the substance to produce a unit change in its temperature. Its SI unit is joules per kelvin or J/K.
We know that to change the temperature of one unit of mass of a substance by one degree, the amount of energy that is required is equivalent to the specific heat capacity of the substance.
So, we can say that specific heat capacity of a substance is
\[c=\dfrac{C}{m}=\dfrac{Q}{\Delta T\times m}\]
Where c is the specific heat capacity,
C is the heat capacity (J/K) of the substance,
Q is the heat energy (joules),
m is the mass of the substance (kg),
and $\Delta T$ is the change in the temperature (K).
Now, the specific heat of ice at 0${}^\circ C$ is 2.05 kJ/kg.K.

Note:
It should be noted that for different substances and different states of matter the specific heat capacity is different. For example, for ${{H}_{2}}O$, the specific heat of liquid water is 4.187 kJ/kg.K, and that of steam or water vapor is 1.996 kJ/kg.K.
It also depends on the starting temperature of the substance and the pressure applied to the substance.