Question

Solve the following: $6x - 1 = 3x + 8$

Answer 1

Hint: In this problem we have given an equation having $x$ variables. Here we are asked to solve this problem. For solving this problem we need to find the value of $x$. To find the value of $x$ we need to keep the $x$ variables on one side and need to take the other numeric values into the other side.

Complete step-by-step solution:
Given that, $6x - 1 = 3x + 8$
Now let us keep the $x$ variables in the left hand side and keep the numeric values in the right hand side.
$ \Rightarrow 6x - 3x = 8 + 1$, negative terms in the left hand side turns to positive when we take it into the right hand side and vice versa.
$ \Rightarrow 3x = 9$
Rearranging the terms,
$ \Rightarrow x = \dfrac{9}{3}$
Dividing the terms we get,
$ \Rightarrow x = 3$

Therefore, the value of $x$ is $3$.

Additional Information: An equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. The most basic and common algebraic equations in math consist of one or more variables. An algebraic equation or polynomial equation is an equation in which both sides are polynomials. These are further classified by degree; linear equation for degree one, quadratic equation for degree two and cubic equation for degree three.

Note: We can solve this by another way of method,
Given that, $6x - 1 = 3x + 8$
Add $1$ on both sides of the given equation,
$6x - 1 + 1 = 3x + 8 + 1$
Hence,
$6x = 3x + 9 - - - \left( 1 \right)$
Subtract $3x$ on both sides of the equation (1),
$6x - 3x = 3x - 3x + 9$
Hence,
$3x = 9$
Rearranging the terms,
$x = \dfrac{9}{3}$
Dividing the terms we get,
$ \Rightarrow x = 3$
Therefore, the value of $x$ is $3$.
This is one of the methods to solve linear equations like in a given.