Answer
Verified
429k+ views
Hint: We use multiplication to solve the LHS of the equation first and then shifting values to suitable sides make an equation where variable is on one side and constant value is on other. We find the value of the variable in the equation and as there is only one unknown variable, i.e. ‘p’ we evaluate the equation for the value of ‘p’.
Complete step-by-step solution:
We have to solve the equation \[4 + 5(p - 1) = 34\].......................… (1)
Since here the variable is ‘p’ in the equation, we will find the value of ‘p’ using operations like multiplication, addition, subtraction and division.
Solve LHS of the equation (1)
Multiply the terms required in the left hand side of the equation
\[ \Rightarrow 4 + 5 \times p - 5 \times 1 = 34\]
Calculate the product in left hand side of the equation
\[ \Rightarrow 4 + 5p - 5 = 34\]
Group the constants in left hand side of the equation
\[ \Rightarrow \left( {4 - 5} \right) + 5p = 34\]
Calculate the value of bracket containing constant terms in left hand side of the equation
\[ \Rightarrow - 1 + 5p = 34\]
Shift all constants to right hand side of the equation
\[ \Rightarrow 5p = 34 + 1\]
Calculate the sum in right hand side of the equation
\[ \Rightarrow 5p = 35\]
Divide both sides of the equation by 5
\[ \Rightarrow \dfrac{{5p}}{5} = \dfrac{{35}}{5}\]
Cancel same factors from numerator and denominator on both sides of the equation
\[ \Rightarrow p = 7\]
So, the value of \[p = 7\]for the equation\[4 + 5(p - 1) = 34\]
\[\therefore \]Solution of the equation \[4 + 5(p - 1) = 34\] is \[p = 7\]
Note: Linear equations in one variable is used when there is only one unknown variable. Linear equations in two variables are used when there are two unknown variables.
Complete step-by-step solution:
We have to solve the equation \[4 + 5(p - 1) = 34\].......................… (1)
Since here the variable is ‘p’ in the equation, we will find the value of ‘p’ using operations like multiplication, addition, subtraction and division.
Solve LHS of the equation (1)
Multiply the terms required in the left hand side of the equation
\[ \Rightarrow 4 + 5 \times p - 5 \times 1 = 34\]
Calculate the product in left hand side of the equation
\[ \Rightarrow 4 + 5p - 5 = 34\]
Group the constants in left hand side of the equation
\[ \Rightarrow \left( {4 - 5} \right) + 5p = 34\]
Calculate the value of bracket containing constant terms in left hand side of the equation
\[ \Rightarrow - 1 + 5p = 34\]
Shift all constants to right hand side of the equation
\[ \Rightarrow 5p = 34 + 1\]
Calculate the sum in right hand side of the equation
\[ \Rightarrow 5p = 35\]
Divide both sides of the equation by 5
\[ \Rightarrow \dfrac{{5p}}{5} = \dfrac{{35}}{5}\]
Cancel same factors from numerator and denominator on both sides of the equation
\[ \Rightarrow p = 7\]
So, the value of \[p = 7\]for the equation\[4 + 5(p - 1) = 34\]
\[\therefore \]Solution of the equation \[4 + 5(p - 1) = 34\] is \[p = 7\]
Note: Linear equations in one variable is used when there is only one unknown variable. Linear equations in two variables are used when there are two unknown variables.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
How do you graph the function fx 4x class 9 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What organs are located on the left side of your body class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell