
How do you solve $ 6m - 4m = - 4\left( {4 - 3m} \right) - 2\left( {2m - 8} \right)? $
Answer
547.5k+ views
Hint: In the above question, we are provided with a linear equation with having “m” as a variable. And we have to find the value of “m”. For such questions, we have to firstly overcome the brackets by multiplying the constants with brackets and then take all the variables along the left=hand side and the constants along the right-hand side.
Complete step by step solution:
The equation given is of the form of a linear equation. A linear equation is defined as that which is of the first order and represents the equation of a straight line. The equation is homogeneous as well because the equation has only one variable which is “m”
The given equation is
$ 6m - 4m = - 4\left( {4 - 3m} \right) - 2\left( {2m - 8} \right) $
Removing the brackets by multiplying the constants outside the brackets,
$\Rightarrow 6m - 4m = - 16 + 12m - 4m + 16 $
Now take all the constants terms to the right-hand side and the variables to the left-hand side.
$\Rightarrow 6m - 4m - 12m + 4m = - 16 + 16 $
Now doing simple addition and subtraction
$ - 6m = 0 $
So, we get $ m = 0 $
This is our final answer.
So, the correct answer is “m=0”.
Note: Just keep in mind when we change the sides of the variables or constants, the signs of the respective constants or variables changes. The positive sign changes to the negative sign and vice-versa. Be careful while copying the equation from the question to the solution part.
Complete step by step solution:
The equation given is of the form of a linear equation. A linear equation is defined as that which is of the first order and represents the equation of a straight line. The equation is homogeneous as well because the equation has only one variable which is “m”
The given equation is
$ 6m - 4m = - 4\left( {4 - 3m} \right) - 2\left( {2m - 8} \right) $
Removing the brackets by multiplying the constants outside the brackets,
$\Rightarrow 6m - 4m = - 16 + 12m - 4m + 16 $
Now take all the constants terms to the right-hand side and the variables to the left-hand side.
$\Rightarrow 6m - 4m - 12m + 4m = - 16 + 16 $
Now doing simple addition and subtraction
$ - 6m = 0 $
So, we get $ m = 0 $
This is our final answer.
So, the correct answer is “m=0”.
Note: Just keep in mind when we change the sides of the variables or constants, the signs of the respective constants or variables changes. The positive sign changes to the negative sign and vice-versa. Be careful while copying the equation from the question to the solution part.
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