
Solve $2y + 9 \geqslant 4$
Answer
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Hint: Since to solve the given problem we need to know about the concept of division and greater than or equal to symbol or inequality.
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $x = \dfrac{{10}}{5} = 2$.
The greater than or equals to inequality is the symbol represented as $ \geqslant $ which means the left-side entries or numbers are greater or equals values than the right-side entries like $x \geqslant y$ where either x is a greater value than y or x equals to y.
Complete step by step answer:
Given that $2y + 9 \geqslant 4$ and we need to find the value of the unknown variable y. now by the subtraction operation, subtract both the values with the number $9$ then we get $2y + 9 - 9 \geqslant 4 - 9$
Further solving we get $2y \geqslant - 5$
Now by the division operation, we get $y \geqslant - \dfrac{5}{2}$ and thus we get $y \geqslant - 2.5$ remainder
Hence the value of the $y$ is either $y > - 2.5$ or $y = - 2.5$ which is the required value.
Example: Which means $y > - 2.5$ is $1 > - 2.5$ where one is positive then it is necessarily greater than negative values.
Note:
The other operations are multiplication, addition and subtraction operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to multiplying the first number. Have a look at an example; while multiplying $5 \times 7$ the number $5$ is called the multiplicand and the number $7$ is called the multiplier. Like $2 \times 3 = 6$ or which can be also expressed in the form of $2 + 2 + 2(3times)$
The addition is the sum of given two or more than two numbers, or variables and in addition, if we sum the two or more numbers then we obtain a new frame of the number will be found, also in subtraction which is the minus of given two or more than two numbers, but here comes with the condition that in subtraction the greater number sign represented in the number will stay constant example $2 - 3 = - 1$
Hence using simple operations, we solved the given problem.
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $x = \dfrac{{10}}{5} = 2$.
The greater than or equals to inequality is the symbol represented as $ \geqslant $ which means the left-side entries or numbers are greater or equals values than the right-side entries like $x \geqslant y$ where either x is a greater value than y or x equals to y.
Complete step by step answer:
Given that $2y + 9 \geqslant 4$ and we need to find the value of the unknown variable y. now by the subtraction operation, subtract both the values with the number $9$ then we get $2y + 9 - 9 \geqslant 4 - 9$
Further solving we get $2y \geqslant - 5$
Now by the division operation, we get $y \geqslant - \dfrac{5}{2}$ and thus we get $y \geqslant - 2.5$ remainder
Hence the value of the $y$ is either $y > - 2.5$ or $y = - 2.5$ which is the required value.
Example: Which means $y > - 2.5$ is $1 > - 2.5$ where one is positive then it is necessarily greater than negative values.
Note:
The other operations are multiplication, addition and subtraction operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to multiplying the first number. Have a look at an example; while multiplying $5 \times 7$ the number $5$ is called the multiplicand and the number $7$ is called the multiplier. Like $2 \times 3 = 6$ or which can be also expressed in the form of $2 + 2 + 2(3times)$
The addition is the sum of given two or more than two numbers, or variables and in addition, if we sum the two or more numbers then we obtain a new frame of the number will be found, also in subtraction which is the minus of given two or more than two numbers, but here comes with the condition that in subtraction the greater number sign represented in the number will stay constant example $2 - 3 = - 1$
Hence using simple operations, we solved the given problem.
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