Question

How do you solve \[2 - 3\left( {x + 4} \right) = 8?\]

Answer 1

Hint: In this question we have to find the $ x $ value from the above algebraic equation. For that we are going to simplify the equation. Next, we rearrange the variables and numbers. Here, Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. In elementary algebra, those symbols represent quantities without fixed values, known as variables. The letters $ x $ and $ y $ represent the areas of the field.

Complete step-by-step solution:
It is given that \[2 - 3\left( {x + 4} \right) = 8\]
To find the $ x $ value:
First we multiply the number 3 into the bracket terms of the above equation and we get
 $ \Rightarrow 2 - 3x - 12 = 18 $
Next, we subtract the numbers in the above equation and we get
 $ \Rightarrow - 10 - 3x = 8 $
Next, we rearrange terms in left hand side (LHS) of the above equation and we get
 $ \Rightarrow - 3x - 10 = 8 $
Then, we add 10 to both sides of the equation and we get
 $ \Rightarrow - 3x - 10 + 10 = 8 + 10 $
Next, cancelling the negative sign in the above equation and we get
 $ \Rightarrow - 3x = 8 + 10 $
Next, we adding the numbers in right hand side (RHS) and we get
 $ \Rightarrow - 3x = 18 $
Then, we divide both sides of the equation by the same term and we get
  $ \Rightarrow \dfrac{{ - 3x}}{{ - 3}} = \dfrac{{18}}{{ - 3}} $
Now, cancel terms that are in both the numerator and denominator. Divide the numbers in both side and we get
 $ \Rightarrow x = - 6 $
Finally, we got the $ x $ value from the given algebraic equation \[2 - 3\left( {x + 4} \right) = 8.\]

Therefore, the final answer is $ x = - 6 $ .

Note: The purpose of algebra is to make it easy to state a mathematical relationship and its equation by using letters of the alphabet or other symbols to represent entities as a form of shorthand. Algebra then allows you to substitute values in order to solve the equations for the unknown quantities.
The main goal of algebra is to develop fluency in working with linear equations. Students will extend their experiences with tables, graphs, and equations and solve linear equations and inequalities and systems of linear equations and inequalities.