Sodium hydroxide reacts with $S{O_2}$ in aqueous medium to give.
A) $NaHS{O_3}$
B) $N{a_2}{S_2}{O_3}$
C) $NaHS{O_4}$
D) $N{a_2}S{O_3}$
Answer
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Hint: We know that Sodium sulfite (sodium sulphite) is the inorganic compound and it can be set up by treating an answer of sodium hydroxide with sulfur dioxide. When directed in warm water, \[N{a_2}S{O_3}\] at first accelerates as a yellow strong. With more \[S{O_2}\], the strong breaks down to give the disulfide, this solidifies after cooling.
Complete step by step solution:
We have to remember that the reaction of sodium hydroxide with Sulphur Dioxide gives Sodium Sulfite and Water. We can write the chemical equation for this reaction is:
\[2NaOH + S{O_2} \to {\text{ }}N{a_2}S{O_3} + {H_2}O\]
Thus option D is correct.
Though, if there is surplus quantity of Sulphur Dioxide, then the Sodium Sulphite so formed reacts with the gas to form Sodium Metabisulphite. The reaction is:
\[N{a_2}S{O_3} + S{O_2}{\text{ }} \to {\text{ }}N{a_2}{S_2}{O_5}\]
If water is present in the reaction then it is different. Sodium Sulfite reacts with Water and Sulphur Dioxide to give Sodium Hydrogensulphite (or Sodium Bisulphate). The reaction is:
\[N{a_2}S{O_3} + {H_2}O + S{O_2}{\text{ }} \to 2NaHS{O_3}\]
Therefore, the option (D) is correct.
Note: We have to know that the ingestion of sulfur dioxide into profoundly amassed sodium hydroxide in a splash section from reproduced pipe gas was researched. The impacts of various working conditions on the \[S{O_2}\] expulsion proficiency, for example, sodium hydroxide fixation, fluid to-gas proportion, gas speed and \[S{O_2}\] focus, were analyzed. The general volume move coefficients, under moderate conditions, were acquired by presenting the immediate and irreversible synthetic response into the two-film hypothesis to build up a model that permitted the figuring of hypothetical estimations of the general volume-move coefficient. It was discovered that the assimilation cycle was constrained by dispersion through gas film when a profoundly thought acidic soft drink arrangement was embraced. The general volume-move coefficient was basically autonomous of convergence of \[S{O_2}\] in the gas stage and decidedly identified with the gas and fluid stream rates.
Complete step by step solution:
We have to remember that the reaction of sodium hydroxide with Sulphur Dioxide gives Sodium Sulfite and Water. We can write the chemical equation for this reaction is:
\[2NaOH + S{O_2} \to {\text{ }}N{a_2}S{O_3} + {H_2}O\]
Thus option D is correct.
Though, if there is surplus quantity of Sulphur Dioxide, then the Sodium Sulphite so formed reacts with the gas to form Sodium Metabisulphite. The reaction is:
\[N{a_2}S{O_3} + S{O_2}{\text{ }} \to {\text{ }}N{a_2}{S_2}{O_5}\]
If water is present in the reaction then it is different. Sodium Sulfite reacts with Water and Sulphur Dioxide to give Sodium Hydrogensulphite (or Sodium Bisulphate). The reaction is:
\[N{a_2}S{O_3} + {H_2}O + S{O_2}{\text{ }} \to 2NaHS{O_3}\]
Therefore, the option (D) is correct.
Note: We have to know that the ingestion of sulfur dioxide into profoundly amassed sodium hydroxide in a splash section from reproduced pipe gas was researched. The impacts of various working conditions on the \[S{O_2}\] expulsion proficiency, for example, sodium hydroxide fixation, fluid to-gas proportion, gas speed and \[S{O_2}\] focus, were analyzed. The general volume move coefficients, under moderate conditions, were acquired by presenting the immediate and irreversible synthetic response into the two-film hypothesis to build up a model that permitted the figuring of hypothetical estimations of the general volume-move coefficient. It was discovered that the assimilation cycle was constrained by dispersion through gas film when a profoundly thought acidic soft drink arrangement was embraced. The general volume-move coefficient was basically autonomous of convergence of \[S{O_2}\] in the gas stage and decidedly identified with the gas and fluid stream rates.
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