Sodium ethoxide is prepared by the reaction of ethanol with aqueous sodium hydroxide.
A) True
B) False
Answer
573k+ views
Hint: To solve this we must know that sodium ethoxide has molecular formula ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{ONa}}$. We must know the products of the reaction when ethanol i.e ethyl alcohol reacts with sodium hydroxide. The molecular formula of ethanol is ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH}}$ and that of sodium hydroxide is ${\text{NaOH}}$.
Complete answer:
We know that sodium ethoxide has molecular formula ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{ONa}}$. Sodium ethoxide is colourless in appearance.
When ethanol $\left( {{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH}}} \right)$ is added to aqueous sodium hydroxide $\left( {{\text{NaOH}}} \right)$, no reaction occurs. This is because aqueous sodium hydroxide contains sodium ions $\left( {{\text{N}}{{\text{a}}^ + }} \right)$ and hydroxide ions $\left( {{\text{O}}{{\text{H}}^ - }} \right)$. In aqueous solution, the sodium ions $\left( {{\text{N}}{{\text{a}}^ + }} \right)$ and hydroxide ions $\left( {{\text{O}}{{\text{H}}^ - }} \right)$ are mobile and thus, ethanol cannot react with the sodium ions to form sodium ethoxide. Thus, we can say that ethanol does not react with aqueous sodium hydroxide.
Sodium ethoxide is prepared by the reaction of ethanol with sodium metal $\left( {{\text{Na}}} \right)$. The reaction of ethanol with sodium metal is as follows:
${\text{2}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH}} + 2{\text{Na}} \to 2{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{ONa}} + {{\text{H}}_2}$
The by-product of the reaction is hydrogen gas. During the reaction, bubbles of hydrogen gas can be observed.
The reaction of ethanol with sodium metal is an acid-base reaction. The reaction helps to show the acidic nature of ethanol. Thus, sodium ethoxide is prepared by the reaction of ethanol with sodium metal.
Thus, the statement ‘sodium ethoxide is prepared by the reaction of ethanol with aqueous sodium hydroxide’ is false.
Thus, the correct option is (B) false.
Note: Ethanol is a very toxic solvent. It is colourless in appearance, has a faint odour and is highly flammable. Ethanol is used as a psychoactive drug. It is an active ingredient in alcoholic beverages. Sodium is a free metal and it does not exist in nature because of its high reactivity.
Complete answer:
We know that sodium ethoxide has molecular formula ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{ONa}}$. Sodium ethoxide is colourless in appearance.
When ethanol $\left( {{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH}}} \right)$ is added to aqueous sodium hydroxide $\left( {{\text{NaOH}}} \right)$, no reaction occurs. This is because aqueous sodium hydroxide contains sodium ions $\left( {{\text{N}}{{\text{a}}^ + }} \right)$ and hydroxide ions $\left( {{\text{O}}{{\text{H}}^ - }} \right)$. In aqueous solution, the sodium ions $\left( {{\text{N}}{{\text{a}}^ + }} \right)$ and hydroxide ions $\left( {{\text{O}}{{\text{H}}^ - }} \right)$ are mobile and thus, ethanol cannot react with the sodium ions to form sodium ethoxide. Thus, we can say that ethanol does not react with aqueous sodium hydroxide.
Sodium ethoxide is prepared by the reaction of ethanol with sodium metal $\left( {{\text{Na}}} \right)$. The reaction of ethanol with sodium metal is as follows:
${\text{2}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{OH}} + 2{\text{Na}} \to 2{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{ONa}} + {{\text{H}}_2}$
The by-product of the reaction is hydrogen gas. During the reaction, bubbles of hydrogen gas can be observed.
The reaction of ethanol with sodium metal is an acid-base reaction. The reaction helps to show the acidic nature of ethanol. Thus, sodium ethoxide is prepared by the reaction of ethanol with sodium metal.
Thus, the statement ‘sodium ethoxide is prepared by the reaction of ethanol with aqueous sodium hydroxide’ is false.
Thus, the correct option is (B) false.
Note: Ethanol is a very toxic solvent. It is colourless in appearance, has a faint odour and is highly flammable. Ethanol is used as a psychoactive drug. It is an active ingredient in alcoholic beverages. Sodium is a free metal and it does not exist in nature because of its high reactivity.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

