How do you simplify\[\left( 2+3i \right)+\left( 7+i \right)\] and write the complex number in the standard form?
Answer
616.8k+ views
Hint: In the given question, we have been asked to simplify the \[\left( 2+3i \right)+\left( 7+i \right)\]. In order to simplify the given expression, first we need to expand the given expression and simplify the numbers. Later we combine the like terms in the given expression. And simplify the expression further and write it into standard form i.e. \[a+bi\]. In this way we will get our required solution.
Complete step-by-step solution:
We have given that,
\[\Rightarrow \left( 2+3i \right)+\left( 7+i \right)\]
Simplifying the above expression, we get
\[\Rightarrow \left( 2+3i \right)+\left( 7+i \right)=2+3i+7+i\]
Combining the like terms in the above expression, we get
\[\Rightarrow 9+4i\]
As, we know that
The standard form of any complex number is\[a+bi\].
\[\Rightarrow 9+4i\]
The above resultant complex number is in standard form.
Therefore, by simplifying \[\left( 2+3i \right)+\left( 7+i \right)\] we get\[9+4i\].
Hence, it is the required solution.
Note: Complex numbers are those numbers which can be written in the form of\[a+bi\], where ‘a’ is the real part and ‘b’ is the imaginary part of the given expression. An imaginary number can be said to be a complex number that can be written as a real number multiplied by the imaginary unit that is iota represented by \[i\]. While solving these types of question, sometimes question include the term \[{{i}^{2}}\] thus students need to remember the property of an imaginary unit that is \[{{i}^{2}}\] = -1. While solving these questions, the first is to expand the brackets i.e. open the brackets in the given expression and write the resultant expression i.e. complex number in the standard form.
Complete step-by-step solution:
We have given that,
\[\Rightarrow \left( 2+3i \right)+\left( 7+i \right)\]
Simplifying the above expression, we get
\[\Rightarrow \left( 2+3i \right)+\left( 7+i \right)=2+3i+7+i\]
Combining the like terms in the above expression, we get
\[\Rightarrow 9+4i\]
As, we know that
The standard form of any complex number is\[a+bi\].
\[\Rightarrow 9+4i\]
The above resultant complex number is in standard form.
Therefore, by simplifying \[\left( 2+3i \right)+\left( 7+i \right)\] we get\[9+4i\].
Hence, it is the required solution.
Note: Complex numbers are those numbers which can be written in the form of\[a+bi\], where ‘a’ is the real part and ‘b’ is the imaginary part of the given expression. An imaginary number can be said to be a complex number that can be written as a real number multiplied by the imaginary unit that is iota represented by \[i\]. While solving these types of question, sometimes question include the term \[{{i}^{2}}\] thus students need to remember the property of an imaginary unit that is \[{{i}^{2}}\] = -1. While solving these questions, the first is to expand the brackets i.e. open the brackets in the given expression and write the resultant expression i.e. complex number in the standard form.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

