How do you simplify the expression $ \dfrac{{\dfrac{y}{x} - \dfrac{x}{y}}}{{\dfrac{{x + y}}{{xy}}}} $ ?
Answer
559.2k+ views
Hint: To solve this problem we should know about addition and subtraction of two fractional numbers. Also about the operation on algebraic variables.
Most important thing we will use to simplify any expression is algebraic formula .
That is,
$ {x^2} - {y^2} = (x - y)(x + y) $
Complete step-by-step answer:
Step 1: solve the numerator part of the given expression:
$ \dfrac{{\dfrac{y}{x} - \dfrac{x}{y}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} $
Step 2: apply algebraic formula to further simplify numerator:
$ \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} $
Step 3: further simply by it by dividing numerator from denominator:
$ \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}\dfrac{{xy}}{{x + y}} $
$ \dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}\dfrac{{xy}}{{x + y}} = y - x $
Hence, simplify equation for $ \dfrac{{\dfrac{y}{x} - \dfrac{x}{y}}}{{\dfrac{{x + y}}{{xy}}}} = y - x $ .
So, the correct answer is “y - x”.
Note: Application of algebra is average word problem, mixture word problem, distance, rate, Time word problem and complex word problem. It is use in our daily life in calculating unknown measures and anything dimension. Algebraic formula used in solving trigonometry and other trigonometric equations.
Most important thing we will use to simplify any expression is algebraic formula .
That is,
$ {x^2} - {y^2} = (x - y)(x + y) $
Complete step-by-step answer:
Step 1: solve the numerator part of the given expression:
$ \dfrac{{\dfrac{y}{x} - \dfrac{x}{y}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} $
Step 2: apply algebraic formula to further simplify numerator:
$ \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} $
Step 3: further simply by it by dividing numerator from denominator:
$ \dfrac{{\dfrac{{{y^2} - {x^2}}}{{xy}}}}{{\dfrac{{x + y}}{{xy}}}} = \dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}\dfrac{{xy}}{{x + y}} $
$ \dfrac{{\left( {y - x} \right)(y + x)}}{{xy}}\dfrac{{xy}}{{x + y}} = y - x $
Hence, simplify equation for $ \dfrac{{\dfrac{y}{x} - \dfrac{x}{y}}}{{\dfrac{{x + y}}{{xy}}}} = y - x $ .
So, the correct answer is “y - x”.
Note: Application of algebra is average word problem, mixture word problem, distance, rate, Time word problem and complex word problem. It is use in our daily life in calculating unknown measures and anything dimension. Algebraic formula used in solving trigonometry and other trigonometric equations.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Give me the opposite gender of Duck class 8 english CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Advantages and disadvantages of science

Full form of STD, ISD and PCO

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE


