Answer
Verified
363k+ views
Hint: To determine the shape of a molecule we should know how to write the Lewis structure and about VSEPR theory. We can draw the Lewis structure of the molecules to determine the electron pair of the central atom. Then by using valence shell electron pair repulsion theory the geometry can be determined.
Complete step-by-step answer :We will write the Lewis structure as follows:
First we will write the basic structure. Then we will decide the central atom around which we will write all atoms of the molecule. The least electronegative atom is the central atom.
Then we will count total valence electrons.
Two electrons are used in the formation of a bond.
So, we will count the total electron used in bond formation.
Then we will subtract the electrons used in bond formation from the total valance electrons.
Then we will arrange the remaining electrons around each atom to complete the octet.
The valence shell electron pair repulsion theory is as follows:
Electron pair is the number of electron pairs present around the central atom in a molecule.
According to VSEPR the electron pairs present around the central atom repel each other. So, all the pairs get arranged to minimize the repulsion. Based on the number of electron pair the geometry can be determined as follows:
Lewis structure of ${\text{ClO}}_2^ - $ ion is as follows:
Total valence electrons in ${\text{ClO}}_2^ - $ are as follows:
$ = \,\left( {7 \times 1} \right) + \left( {6 \times 2} \right) + 1$
$ = \,20$
The total electron pair around central atom chlorine is four so, the geometry will be tetrahedral which is shown as follows:
All four electron pairs are not the same,out of four two are bond pairs and two are lone pairs.
So, the shape of ${\text{ClO}}_2^ - $ ion is angular.
Therefore, option (B) Angular, is correct.
Note:To determine the total valence electrons of a molecule, sum all the valance electron of the atoms present in the molecule. Subtract one for every positive charge and add one for every negative charge. Geometry around the central atom is decided only on the basis of sigma bond pair and lone pair only. Pi bonds are not counted to determine the geometry. Geometry is decided by counting the number of lone pair and sigma bonds where the shape is determined on the basis of sigma bond pairs only.
Complete step-by-step answer :We will write the Lewis structure as follows:
First we will write the basic structure. Then we will decide the central atom around which we will write all atoms of the molecule. The least electronegative atom is the central atom.
Then we will count total valence electrons.
Two electrons are used in the formation of a bond.
So, we will count the total electron used in bond formation.
Then we will subtract the electrons used in bond formation from the total valance electrons.
Then we will arrange the remaining electrons around each atom to complete the octet.
The valence shell electron pair repulsion theory is as follows:
Electron pair is the number of electron pairs present around the central atom in a molecule.
According to VSEPR the electron pairs present around the central atom repel each other. So, all the pairs get arranged to minimize the repulsion. Based on the number of electron pair the geometry can be determined as follows:
Number of electron pair | Geometry |
$2$ | Linear |
$3$ | Trigonal planar |
$4$ | Tetrahedral |
$5$ | Trigonal bipyramidal |
$6$ | Octahedral |
Lewis structure of ${\text{ClO}}_2^ - $ ion is as follows:
Total valence electrons in ${\text{ClO}}_2^ - $ are as follows:
$ = \,\left( {7 \times 1} \right) + \left( {6 \times 2} \right) + 1$
$ = \,20$
The total electron pair around central atom chlorine is four so, the geometry will be tetrahedral which is shown as follows:
All four electron pairs are not the same,out of four two are bond pairs and two are lone pairs.
So, the shape of ${\text{ClO}}_2^ - $ ion is angular.
Therefore, option (B) Angular, is correct.
Note:To determine the total valence electrons of a molecule, sum all the valance electron of the atoms present in the molecule. Subtract one for every positive charge and add one for every negative charge. Geometry around the central atom is decided only on the basis of sigma bond pair and lone pair only. Pi bonds are not counted to determine the geometry. Geometry is decided by counting the number of lone pair and sigma bonds where the shape is determined on the basis of sigma bond pairs only.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
How do you solve x2 11x + 28 0 using the quadratic class 10 maths CBSE
Select the correct plural noun from the given singular class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
The sum of three consecutive multiples of 11 is 363 class 7 maths CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How many squares are there in a chess board A 1296 class 11 maths CBSE