
Roshan spends $80\%$ of the money that he receives every month and saves ₹ \[2500\]. How much money does he get monthly?
Answer
508.2k+ views
Hint: In this question we have been given with the data Roshan spends $80\%$ of the money given to him every month and he saves ₹ $2500$. We will solve this problem by considering the monthly amount that Roshan gets to be $x$. We will then subtract the $80\%$ of the amount $x$ which will give us the amount he saves. We will then equate the given amount $2500$ with the amount saved and solve for the value of $x$ to get the amount he gets monthly.
Complete step by step answer:
We know from the question that Roshan spends $80\%$ of the money that he receives and saves ₹ \[2500\].
Let the amount which Roshan gets every month be $x$.
And since he spends $80\%$ of the amount, we can write it in mathematical form as:
$\Rightarrow x-80\%\text{ of }x$
We can rewrite the expression as:
$\Rightarrow x-\dfrac{80x}{100}$
On taking the lowest common multiple for both the terms, we get:
$\Rightarrow \dfrac{100x-80x}{100}$
On subtracting the terms in the numerator, we get:
$\Rightarrow \dfrac{20x}{100}$
On simplifying the fractions, we get:
$\Rightarrow \dfrac{x}{5}$, which is the amount he saves monthly.
Now since we know that he saves ₹ $2500$, we can equate and write it as:
$\Rightarrow \dfrac{x}{5}=2500$
On transferring the term from the left-hand side to the right-hand side, we get:
$\Rightarrow x=5\times 2500$
On multiplying the terms, we get:
$\Rightarrow x=12500$, which is the required monthly amount.
Therefore, the monthly amount that Roshan receives is ₹ $12500$, which is the required solution.
Note: Whenever there is addition or subtraction of two fractions, the lowest common multiple should always be taken to get the denominator of both the fractions the same. It is to be remembered that the symbol of rupee has now become ₹ instead of the traditional symbols which were Rs And Re.
Complete step by step answer:
We know from the question that Roshan spends $80\%$ of the money that he receives and saves ₹ \[2500\].
Let the amount which Roshan gets every month be $x$.
And since he spends $80\%$ of the amount, we can write it in mathematical form as:
$\Rightarrow x-80\%\text{ of }x$
We can rewrite the expression as:
$\Rightarrow x-\dfrac{80x}{100}$
On taking the lowest common multiple for both the terms, we get:
$\Rightarrow \dfrac{100x-80x}{100}$
On subtracting the terms in the numerator, we get:
$\Rightarrow \dfrac{20x}{100}$
On simplifying the fractions, we get:
$\Rightarrow \dfrac{x}{5}$, which is the amount he saves monthly.
Now since we know that he saves ₹ $2500$, we can equate and write it as:
$\Rightarrow \dfrac{x}{5}=2500$
On transferring the term from the left-hand side to the right-hand side, we get:
$\Rightarrow x=5\times 2500$
On multiplying the terms, we get:
$\Rightarrow x=12500$, which is the required monthly amount.
Therefore, the monthly amount that Roshan receives is ₹ $12500$, which is the required solution.
Note: Whenever there is addition or subtraction of two fractions, the lowest common multiple should always be taken to get the denominator of both the fractions the same. It is to be remembered that the symbol of rupee has now become ₹ instead of the traditional symbols which were Rs And Re.
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