Predict the product of electrolysis in an aqueous solution of $ CuC{l_2} $ with platinum electrodes?
Answer
552k+ views
Hint :Electrolysis is the process of passing of direct current through the electrodes , such that the chemical reaction takes place and the products are formed near each electrode i.e. anode and cathode .
Complete Step By Step Answer:
As we know a complete setup of electrochemical cells is required for the reaction to take place. It includes electrolytes, electrodes, external circuits and salt bridges.
In our case, we have to answer the products formed when aqueous solution of $ CuC{l_2} $ undergoes in reaction with platinum electrodes.
So, now we have basic knowledge about electrolysis and electrodes. So, two types of electrodes are used: cathode – negative and anode-positive.
So, in our electrolyte $ CuC{l_2} $
$ Cu $ (Copper), having lower discharge potential than hydrogen will undergo reduction reaction near the cathode.
Reaction as follows –
At Cathode:
$ C{u^{2 + }} + 2e \to Cu $
So, $ Cu $ being the positive molecule, will be collected near the negative cathode
Next, at our Anode,
$ 2C{l^ - } \to C{l_2} + 2{e^ - } $
So, chloride ions will be oxidized at the positive anode.
Therefore our products formed on electrolysis in an aqueous solution of $ CuC{l_2} $ with platinum electrodes are copper, $ Cu $ (at cathode) and chlorine, $ C{l_2} $ (at anode).
Note :
To know or understand what product will be formed at which anode, one has to look for the half reaction of the electrolytic cell or better say the electrode potential of the half cell. There is standard electrode potential for every molecule.
Complete Step By Step Answer:
As we know a complete setup of electrochemical cells is required for the reaction to take place. It includes electrolytes, electrodes, external circuits and salt bridges.
In our case, we have to answer the products formed when aqueous solution of $ CuC{l_2} $ undergoes in reaction with platinum electrodes.
So, now we have basic knowledge about electrolysis and electrodes. So, two types of electrodes are used: cathode – negative and anode-positive.
So, in our electrolyte $ CuC{l_2} $
$ Cu $ (Copper), having lower discharge potential than hydrogen will undergo reduction reaction near the cathode.
Reaction as follows –
At Cathode:
$ C{u^{2 + }} + 2e \to Cu $
So, $ Cu $ being the positive molecule, will be collected near the negative cathode
Next, at our Anode,
$ 2C{l^ - } \to C{l_2} + 2{e^ - } $
So, chloride ions will be oxidized at the positive anode.
Therefore our products formed on electrolysis in an aqueous solution of $ CuC{l_2} $ with platinum electrodes are copper, $ Cu $ (at cathode) and chlorine, $ C{l_2} $ (at anode).
Note :
To know or understand what product will be formed at which anode, one has to look for the half reaction of the electrolytic cell or better say the electrode potential of the half cell. There is standard electrode potential for every molecule.
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