Answer
Verified
444k+ views
Hint: We know that the electric force is force experience due multiple charges, and is given by Coulomb's force. It states that the electric force depends on the charge q and inversely proportional to the square of the distance between them. We can use the above to solve the given problem..
Formula: $F=k\dfrac{q_{1}q_{2}}{r^{2}}$
Complete answer:
We know that the electric force is the force experienced due to a pair charges is given by Coulomb's force. Clearly, the electrical force between the charges, depends on the individual charge q and is inversely proportional to the square of the distance between them.
We know that, the electrical force $F$ between two charges $q_{1}$ and $q_{2}$ which is separated at a distance $r$ is given as $F=k\dfrac{q_{1}q_{2}}{r^{2}}$, where $k=\dfrac{1}{4\pi\epsilon_{0}}$ which is constant with a value $9\times 10^{9}$.
Similarly, an electric field E is defined as the electric force F per unit positive charge q, which is infinitesimally small and at rest, and is given as $E=\dfrac{F}{q}$. Then $E=\dfrac{kq}{r^{2}}$.
Here, given that the $-q$ is kept at a point, say, P at the axial point, at a distance $x$ from the ring.
We know that the electric field due to a circular ring, of radius $R$ and charge $Q$ i is given as $E=\dfrac{kQx}{(R^{2}+x^{2})^{\dfrac{3}{2}}}$
$\implies E=\dfrac{kQx}{R^{3}}$
Then the force at P is given as, $F=qE=\dfrac{kQqx}{R^{3}}$
Let the amplitude of the electric field be $x$, then the time period of the electric field is given as
$T=2\pi\sqrt{\dfrac{x}{\dfrac{kQqx}{mR^{3}}}}$
$\implies T=2\pi\sqrt{\dfrac{mR^{3}x}{kQqx}}$
$\implies T=2\pi\sqrt{\dfrac{4\pi\epsilon_{0}mR^{3}}{Qq}}$
$\therefore T=\sqrt{\dfrac{16\pi^{2}\epsilon_{0}mR^{3}}{Qq}}$ is the time period of the electric field.
Note:
We know that the electric force due to a pair of charges is given by Coulomb's law. This force can be attractive or repelling depending on the nature of the charges. Electric field is in the direction of the force. However, the electric field also depends on the symmetry of the charge carrying conductor.
Formula: $F=k\dfrac{q_{1}q_{2}}{r^{2}}$
Complete answer:
We know that the electric force is the force experienced due to a pair charges is given by Coulomb's force. Clearly, the electrical force between the charges, depends on the individual charge q and is inversely proportional to the square of the distance between them.
We know that, the electrical force $F$ between two charges $q_{1}$ and $q_{2}$ which is separated at a distance $r$ is given as $F=k\dfrac{q_{1}q_{2}}{r^{2}}$, where $k=\dfrac{1}{4\pi\epsilon_{0}}$ which is constant with a value $9\times 10^{9}$.
Similarly, an electric field E is defined as the electric force F per unit positive charge q, which is infinitesimally small and at rest, and is given as $E=\dfrac{F}{q}$. Then $E=\dfrac{kq}{r^{2}}$.
Here, given that the $-q$ is kept at a point, say, P at the axial point, at a distance $x$ from the ring.
We know that the electric field due to a circular ring, of radius $R$ and charge $Q$ i is given as $E=\dfrac{kQx}{(R^{2}+x^{2})^{\dfrac{3}{2}}}$
$\implies E=\dfrac{kQx}{R^{3}}$
Then the force at P is given as, $F=qE=\dfrac{kQqx}{R^{3}}$
Let the amplitude of the electric field be $x$, then the time period of the electric field is given as
$T=2\pi\sqrt{\dfrac{x}{\dfrac{kQqx}{mR^{3}}}}$
$\implies T=2\pi\sqrt{\dfrac{mR^{3}x}{kQqx}}$
$\implies T=2\pi\sqrt{\dfrac{4\pi\epsilon_{0}mR^{3}}{Qq}}$
$\therefore T=\sqrt{\dfrac{16\pi^{2}\epsilon_{0}mR^{3}}{Qq}}$ is the time period of the electric field.
Note:
We know that the electric force due to a pair of charges is given by Coulomb's law. This force can be attractive or repelling depending on the nature of the charges. Electric field is in the direction of the force. However, the electric field also depends on the symmetry of the charge carrying conductor.
Recently Updated Pages
Identify the feminine gender noun from the given sentence class 10 english CBSE
Your club organized a blood donation camp in your city class 10 english CBSE
Choose the correct meaning of the idiomphrase from class 10 english CBSE
Identify the neuter gender noun from the given sentence class 10 english CBSE
Choose the word which best expresses the meaning of class 10 english CBSE
Choose the word which is closest to the opposite in class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
A rainbow has circular shape because A The earth is class 11 physics CBSE
The male gender of Mare is Horse class 11 biology CBSE
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths