
One coulomb charge is equivalent to the charge contained in:
\[\begin{align}
& A.26\times {{10}^{19}}electrons \\
& B.6.2\times {{10}^{19}}electrons \\
& C.2.65\times {{10}^{18}}electrons \\
& D.6.25\times {{10}^{18}}electrons \\
\end{align}\]
Answer
575.7k+ views
Hint: Coulomb is the SI unit of charge. It is the number of electrons that flow through a conductor to produce one ampere current in one second. Also, from Coulomb's law, it is the amount of charge required to produce a unit force between two charges, which are separated at a distance of $1\;m$ from each other.
Complete step by step answer:
We know that electric charge $q$ is the property of a matter. It is due to the application of electric fields on the given matter. The charges are broadly of two types namely, positive or protons and negative or electrons. Also, like charges repel and unlike charges attract. Which is to say that a pair of protons or electrons repel each other, while a proton and an electron attract each other.
Let $q$ be the charge on an electron $e$, then we can say that $q=ne$, where $n$ is the number of electrons.
On rearranging, we get$\implies n=\dfrac{q}{e}$
We know that charge of an electron is $e=1.6\times 10^{-19}C$. Then for $q=1$, substituting the values, we get, $n=\dfrac{1}{1.6\times 10^{-19}}=0.625\times 10^{19}=6.25\times 10^{18} electrons$
Thus the answer is \[D.6.25\times {{10}^{18}}electrons\]
Additional information:
The term coulomb, is named after the scientist Charles-Augustin de Coulomb.
Also, faraday is the total charge present in one mole of charges. It is given as $F=96485.332C$, where $1mol=6.022\times 10^{23}$ charges.
Also, the flow of current for a duration of one hour produces $3600C\;$ of charges.
Note:
It is the charge carried by the fundamental or elementary particle. However, this can be expressed in terms of multiples of $10^{-1}$ called desicolumbus to $10^{24}$ called yotta coulomb. It is suggested to remember that the charge of electron is $e=1.6\times 10^{-19}C$, and there are $6.25\times {{10}^{18}}electrons$ in one coulomb charge $1\;C$.
Complete step by step answer:
We know that electric charge $q$ is the property of a matter. It is due to the application of electric fields on the given matter. The charges are broadly of two types namely, positive or protons and negative or electrons. Also, like charges repel and unlike charges attract. Which is to say that a pair of protons or electrons repel each other, while a proton and an electron attract each other.
Let $q$ be the charge on an electron $e$, then we can say that $q=ne$, where $n$ is the number of electrons.
On rearranging, we get$\implies n=\dfrac{q}{e}$
We know that charge of an electron is $e=1.6\times 10^{-19}C$. Then for $q=1$, substituting the values, we get, $n=\dfrac{1}{1.6\times 10^{-19}}=0.625\times 10^{19}=6.25\times 10^{18} electrons$
Thus the answer is \[D.6.25\times {{10}^{18}}electrons\]
Additional information:
The term coulomb, is named after the scientist Charles-Augustin de Coulomb.
Also, faraday is the total charge present in one mole of charges. It is given as $F=96485.332C$, where $1mol=6.022\times 10^{23}$ charges.
Also, the flow of current for a duration of one hour produces $3600C\;$ of charges.
Note:
It is the charge carried by the fundamental or elementary particle. However, this can be expressed in terms of multiples of $10^{-1}$ called desicolumbus to $10^{24}$ called yotta coulomb. It is suggested to remember that the charge of electron is $e=1.6\times 10^{-19}C$, and there are $6.25\times {{10}^{18}}electrons$ in one coulomb charge $1\;C$.
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